Information Technology Reference
In-Depth Information
ω p1 = 1/[(R s + R D )C GD + (R s + 1/ g m )0.5 C GS + R D C DB )] . (3)
ω p2 = 1/ K [R s R D (C GD C DB + C GD C DB + C GD C DB )] . (4)
Where, K = ( C GD C DB + C GD C GS + C GS C DB ) (R s + 1/ g m ) R D + (R D / g m )
(C DB + C GD + C GS ) (C DB + C GD + C GS3 + C DB3 ) +
R D [R s C GD ( C GD + C DB ) + C DS C DS/ g m )] .
where R S is the resistance of the voltage sources (not shown in the figure) connected
at the inputs, the transconductance, and the capacitances are for the transistors M 1 and
M 2 (which are assumed to be identical), unless there is a subscript “3” in the name, in
which case they refer to the transistor M 3 .Comparison of Eqns. (1) and (3) shows
that the proposed architecture has a much higher dominant pole frequency,
compared to the conventional CML buffer, Moreover, due to the source-coupled
configuration of the former, two gate-source capacitances (C GS ) are seen in series by
the input terminal, thus reducing this capacitance by a factor of 2 in the dominant pole
expression.
Design Issues
4
The load resistor R is determined by impedance matching requirements (being
typically between 50
Ω
Ω
Ω
and 100
) and was taken to be 75
. For a given
voltage swing (V SWING ), the current I SS is given by I SS = V SWING /R D .
For the entire tail current to flow only in one branch [1],
0.5V in > [ 2I SS L / µ CoxW ] 1/2 .
(5)
from which W 1 can be calculated. Also, for keeping the current source in saturation,
V CM - V GS > V BIAS - V T .
(6)
which yields,
W 1 > 2I SS L / µ CoxW( V CM - V BIAS ) 2 .
(7)
W 1 then must be chosen to satisfy both Eqns. (5) and (7).
Search WWH ::




Custom Search