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+B 13 3
x 1
x 2
[ k 1 ]
3
x 1
x 2
[ k 2 ]
A 1 k 1
A 1 k 2
k 1 =1
k 2 =1
3
[ k 3 ] =
x 1
x 2
A 1 k 3
(B.51)
k 3 =1
=B 11 A 11 x 1
+(B 11 A 12 +B 12 A 11 A 11 ) x 1
[2]
+
x 2
x 2
+[B 11 A 13 +B 12 (A 11
A 12 +A 12
A 11 )+B 13 (A 11
A 11
A 11 )]
x 1
x 2
[3]
+ β 14 .
2nd polynomial:
x 1
x 2
x 1
x 2
= x 1
[2]
=B 22 y 1
[2]
+B 23 y 1
[3]
+ β 24 =
x 2
y 2
y 2
(B.52)
A 11 ) x 1
[2]
=B 22 (A 11
+[B 22 (A 11
A 12 +A 12
A 11 )
x 2
A 11 )] x 1
[3]
+ β 24 .
+B 23 (A 11
A 11
x 2
3rd polynomial:
x 1
x 2
x 1
x 2
x 1
x 2
= x 1
[3]
A 11 ) x 1
[3]
+ β 34 .
=B 33 (A 11
A 11
(B.53)
x 2
x 2
Forward substitution:
x 1
x 2
[1]
x 1
x 2
[1]
x 1
x 2
[2]
x 1
x 2
[2]
β 14
β 24
β 34
B 11 B 12 B 13
OB 22 B 23
00B 33
A 11 A 12 A 13
0A 22 A 23
00A 33
=
,
=
+
(B.54)
x 1
x 2
[3]
x 1
x 2
[3]
subject to
A 22 =A 11
A 11 , A 23 =A 11
A 12 +A 12
A 11 , A 33 =A 11
A 11
A 11 .
(B.55)
Both the matrices A :=
A and B :=
B are upper triangular such that
1
B =I 14
B =
A .
(B.56)
A
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