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+B
13
3
x
1
x
2
[
k
1
]
3
x
1
x
2
[
k
2
]
A
1
k
1
⊗
A
1
k
2
k
1
=1
k
2
=1
3
[
k
3
]
=
x
1
x
2
⊗
A
1
k
3
(B.51)
k
3
=1
=B
11
A
11
x
1
+(B
11
A
12
+B
12
A
11
⊗
A
11
)
x
1
[2]
+
x
2
x
2
+[B
11
A
13
+B
12
(A
11
⊗
A
12
+A
12
⊗
A
11
)+B
13
(A
11
⊗
A
11
⊗
A
11
)]
x
1
x
2
[3]
+
β
14
.
2nd polynomial:
x
1
x
2
x
1
x
2
=
x
1
[2]
=B
22
y
1
[2]
+B
23
y
1
[3]
+
β
24
=
⊗
x
2
y
2
y
2
(B.52)
A
11
)
x
1
[2]
=B
22
(A
11
⊗
+[B
22
(A
11
⊗
A
12
+A
12
⊗
A
11
)
x
2
A
11
)]
x
1
[3]
+
β
24
.
+B
23
(A
11
⊗
A
11
⊗
x
2
3rd polynomial:
x
1
x
2
x
1
x
2
x
1
x
2
=
x
1
[3]
A
11
)
x
1
[3]
+
β
34
.
⊗
⊗
=B
33
(A
11
⊗
A
11
⊗
(B.53)
x
2
x
2
Forward substitution:
⎡
⎤
⎡
⎤
x
1
x
2
[1]
x
1
x
2
[1]
⎣
⎦
⎣
⎦
⎡
⎤
⎡
⎤
⎡
⎤
x
1
x
2
[2]
x
1
x
2
[2]
β
14
β
24
β
34
B
11
B
12
B
13
OB
22
B
23
00B
33
A
11
A
12
A
13
0A
22
A
23
00A
33
⎣
⎦
⎣
⎦
=
⎣
⎦
,
=
+
(B.54)
x
1
x
2
[3]
x
1
x
2
[3]
subject to
A
22
=A
11
⊗
A
11
,
A
23
=A
11
⊗
A
12
+A
12
⊗
A
11
,
A
33
=A
11
⊗
A
11
⊗
A
11
.
(B.55)
Both the matrices A :=
A
and B :=
B
are upper triangular such that
−
1
B
=I
14
⇔
B
=
A
.
(B.56)
A
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