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Backward substitution:
⎡
⎤
⎡
⎤
B
11
B
12
B
13
0B
22
B
23
00B
33
A
11
A
12
A
13
0A
22
A
23
00A
33
⎣
⎦
⎣
⎦
=I
14
;
B
=I
14
⇔
(B.57)
A
(i)B
11
A
11
=I
2
⇒
B
11
=A
−
1
11
;
(ii)B
12
A
12
+B
12
A
22
=0
⇒
11
A
12
A
−
1[2]
B
11
A
12
A
−
1
A
−
1
B
12
=
−
22
=
−
22
;
(B.58)
(iii)B
11
A
13
+B
12
A
23
+B
13
A
33
=0
⇒
(B
11
A
13
+B
12
A
23
)A
−
1
B
13
=
−
33
=
11
A
13
A
−
1[3]
11
A
12
A
−
1[2]
11
(A
11
⊗
A
12
+A
12
⊗
A
11
)A
−
1[3]
=
−
A
−
1
+A
−
1
11
11
=A
−
1
A
13
+A
12
(A
−
1
A
−
1
A
11
)](A
−
1
A
−
1
11
A
−
1
11
[
−
⊗
11
)(A
11
⊗
A
12
+A
12
⊗
⊗
11
)
.
11
11
First, we have used (
A⊗B
)
−
1
=
A
−
1
⊗B
−
1
for two invertible square matrices
A
and
B
, secondly
we have used the standard solution of a system of upper triangular matrix equations. For the
inverse polynomial representation, only the elements of the first row of the matrix B :=
B
are
of interest. An explicit write-up is
x
1
x
2
=A
−
1
y
1
y
2
11
)
y
1
[2]
A
−
1
11
A
12
(A
−
1
A
−
1
−
⊗
−
11
11
y
2
A
−
1
A
12
(A
−
1
A
−
1
−
11
[A
13
−
⊗
11
)(A
11
⊗
A
12
+A
12
⊗
A
11
)]
11
11
)
y
1
[3]
(A
−
1
⊗
A
−
1
⊗
A
−
1
.
(B.59)
11
11
y
2
End of Example.
B-3 Inversion of a Multivariate Homogeneous Polynomial of Degree
n
Assume a multivariate homogeneous polynomial of degree
n
,namely
y
(
x
), to be given and find
the inverse multivariate homogeneous polynomial of degree
n
,namely
x
(
y
), and
n
y
(
x
)=A
11
x
+A
12
x
[2]
+
···
+A
1
n−
1
x
[
n−
1]
+A
1
n
x
[
n
]
=
A
1
k
x
[
k
]
p
,
∀
x
∈
R
k
=1
(B.60)
n
x
(
y
)=B
11
y
+B
12
y
[2]
+
···
+B
1
n−
1
y
[
n−
1]
+B
1
n
y
[
n
]
=
B
1
k
y
[
k
]
p
,
∀
y
∈
R
k
=1
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