Geography Reference
In-Depth Information
d α = A 1 1 − E 2 cos 2 α, s 2 ( α ):= 1
s 1 ( α ):= d s
d α 2 = 1
d 2 s
A 1 E 2 sin α cos α
1
E 2 cos 2 α .
(16.33)
2!
2
End of Corollary.
Proof.
1
A 1
E
:
,A 2
A 1 1
d s = d x 2 +d y 2 = A 1 1
E 2 sin 2 α d α
E 2 cos 2 α d α =
s ( α )= A 1 α
0
1
E 2 cos 2 α d α =
(16.34)
A 1 α
π/ 2
E 2 sin 2 α d α = A 1 π/ 2
α
1
1
E 2 sin 2 α d α =
=
= A 1 π/ 2
0
1 − E 2 sin 2 α d α − A 1 α
0
1 − E 2 sin 2 α d α =
E 2 sin 2 i
1 − E 2 cos 2 i .
= A 1 [ E ( π/ 2; E )
E ( α ; E )]
E 2 =
End of Proof.
Proof.
1 · 1
2
1 · 1 · 3
2
1 · 1 · 3 · 5
2
1
2 x
x ) 1 / 2 =1
4 x 2
6 x 3
8 x 4
(1
−··· ∀|
x
|≤
1 ,
(16.35)
·
·
4
·
·
4
·
6
·
1
1
1 · 1
2
1 · 1 · 3
2
2 E 2 cos 2 α
4 E 4 cos 4 α
6 E 6 cos 6 α
E 2 cos 2 α =1
(16.36)
·
·
4
·
1 · 1 · 3 · 5
2
1 · 1 · 3 · 5 · 7
2
8 E 8 cos 8 α
10 E 10 cos 10 α O( E 12 ) ∀E < 1 .
·
4
·
6
·
·
4
·
6
·
8
·
These series are uniformly convergent. Accordingly, in the arc length integral, we can interchange
integration and summation and are directly led to ( 16.31 ).
End of Proof.
The proof for ( 16.32 ) is now straightforward. In Corollary 16.3 , the relation of meta-longitude α
to longitude L and latitude B is summarized.
Corollary 16.3 (Cha-cha-cha: meta-longitude α versus longitude L and latitude B ).
Ω )= 1
tan( L
E 2 cos i tan α,
(16.37)
 
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