Environmental Engineering Reference
In-Depth Information
6.4.4 Summary and Remarks
Summary
The solution of
u t
τ 0 +
B 2
A 2
u tt =
Δ
u
+
t Δ
u
+
f
(
M
,
t
) ,
Ω × (
0
, + ) ,
(6.90)
L
(
u
,
u n ) | ∂Ω =
0
,
u
(
M
,
0
)= ϕ (
M
) ,
u t (
M
,
0
)= ψ (
M
)
is
1
τ
W ϕ (
0 +
B 2 W λ mnk ϕ (
u
=
M
,
t
)+
M
,
t
)
t
t
+
W ψ (
M
,
t
)+
W f τ ( M , t τ )
(6.91)
0
where
0
<
x
<
l 1 ,
one-dimensional case
,
Ω
:
0
<
x
<
l 1 ,
0
<
y
<
l 2 ,
two-dimensional case
,
0
<
x
<
l 1 ,
0
<
y
<
l 2 ,
0
<
z
<
l 3 ,
three-dimensional case
.
Ω .
∂Ω
: the boundary of
λ
,
one-dimensional case
,
m
λ mnk =
λ m + λ n ,
two-dimensional case
,
λ m + λ n + λ k ,
three-dimensional case
.
M m ,
one-dimensional case
,
M mnk =
M m M n ,
two-dimensional case
,
M m M n M k ,
three-dimensional case
.
X m (
x
) ,
one-dimensional case
,
F mnk (
M
)=
X m (
x
)
Y n (
y
) ,
two-dimensional case
,
X m (
x
)
Y n (
y
)
Z k (
z
) ,
three-dimensional case
.
 
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