Environmental Engineering Reference
In-Depth Information
1
τ 0 + λ
m B 2
1
2
,
,
one-dimensional case
1
τ 0 + λ
mn B 2
1
2
α mnk =
,
two-dimensional case
,
1
τ 0 + λ mnk B 2
1
2
,
.
three-dimensional case
2 4
1
λ m A 2
4
α
m
,
one-dimensional case
,
2 4
1
β mnk =
λ mn A 2
4
α
mn
,
two-dimensional case
,
4
1
2
2
λ mnk A 2
4
α
mnk ,
three-dimensional case
.
f
(
x
, τ ) ,
one-dimensional case
,
f τ =
f
(
M
, τ )=
f
(
x
,
y
, τ ) ,
two-dimensional case
,
f
(
x
,
y
,
z
, τ ) ,
three-dimensional case
.
W ψ (
M
,
t
)
is the solution at f
= ϕ =
0, i.e.
)= m , n , k B mnk F mnk ( M ) e α mnk t sin β mnk t ,
u
=
W ψ (
M
,
t
(6.92)
1
M mnk β mnk
B mnk =
Ω ψ (
M
)
F mnk (
M
)
d
Ω .
Here the integral
is the definite integral, the double integral and the triple inte-
gral depending on the dimensions of
Ω
Ω
.Thed
Ω
stands for d x ,d x d y and d x d y d z ,
respectively.
Remarks
1. To apply the solution structure theorem and the Fourier method of expansion, the
boundary conditions must be linear, homogeneous, separable and with constant
coefficients. The ordinals m , n and k cannot be confused. Their starting value (0
or 1) depends on the boundary conditions. We should also pay attention to the
symbol change of h 1 and h 2 etc.
2. The
μ n and
μ k
μ m ,
μ n and
μ k carry different meanings. We should use
to distin-
guish if necessary. Note also that the
μ m have different definitions in Rows 3, 6
and9inTable2.1.
m , n is a double summation in the two-dimensional case. Taking the starting values
of m and n equal to 1 as the example, coefficients B mn read
3.
 
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