Biomedical Engineering Reference
In-Depth Information
triangle ABD is pushed into the segment of the chip. At point D, the shear
along DF begins and segment DHCF is completed. HC and DF meet at R, the
centre of the circle of the chip segment. Since the angle HRD is small, RD
may be referred to as the radius of the chip. The clearance angle is .
Triangles ABD and HBC are equal in area and the depth of cut FG is
equal to d. The spacing between the segments, i.e., the lamellae, is CE, which
is equal to BD, which is equal to s. The chip thickness between lamellae, TC,
is equal to t, whilst the rake angle SBD is equal to
. The cutting tool bends
when machining compact bone, which reduces the effective rake angle to
b
.
We know that the chip radius r can be taken as RD, whilst the shear angle
subtended is BÂD, or
.
The calculation of the chip radius is provided by the following analysis,
s
.
cos(
)
DP =
(23)
b
B
.
S
AB =
(24)
sin
where,
s
.
cos
BS =
(25)
b
Thus,
d
DF = AC =
(26)
sin
And,
s
.
cos
b
AB =
(27)
sin
Now,
