Biomedical Engineering Reference
In-Depth Information
d
s
.
cos
b
(28)
BC = AC - AB =
sin
sin
Therefore,
(
d
s
.
cos
)
b
BC =
(29)
sin
The areas of ABD and HBC are equal, such that,
AB.DP = HQ.BC
(30)
Hence,
DP
.
AB
s
.
cos
.
s
.
cos(
).
sin
(31)
b
b
HQ
BC
sin
.(
d
s
.
cos
)
b
And thus,
2
s
.
cos
.
cos(
)
(32)
b
s
b
HQ
(
d
.
cos
)
b
Also,
2
HQ
s
.
cos
(33)
b
BH
cos(
)
(
d
s
.
cos
)
b
b
And,
s
2
.
cos
(34)
DH
BH
BD
s
b
(
d
s
.
cos
)
b
Such that,
s
.
d
(35)
DH
(
d
s
.
cos
)
b
