Geoscience Reference
In-Depth Information
Taking the dot product of the equation in (4.11) with the differential position
vector defined by (4.12), we find that
p
0
1
Dv
=
Dt
dr
¼
J
ð
2
v
v
Þ
E
dr
þ½ð
JT
v
Þ
T
v
E
dr
¼
0
J
dr
þ
Bdz
ð
4
:
13
Þ
E
E
E
Integrating (4.13) along a streamline (v), it follows that the Lamb term
½ð
JT
v
Þ
T
v
is zero, because
½ð
JT
v
Þ
T
v
E
v
¼
0, and so
ð
ð
Þ
dx
þ
Ð
@=@
2
2
2
1
1
1
@=@
x
ð
2
j
v
j
y
ð
2
j
v
j
Þ
dy
þ
@=@
z
ð
2
j
v
j
Þ
dz
ð
ð
Bdz
ð
4
p
0
p
0
p
0
¼
0
ð@
=@
xdx
þ@
=@
ydy
þ@
=@
zdz
Þþ
:
14
Þ
Since the LHS of (4.14) may be expressed as
ð
d
ð
2
1
2
j
v
j
Þ
, it follows that
ð
d
ð
Þþ
0
ð
dp
0
ð
Bdz
¼
0
2
1
2
j
v
j
ð
4
:
15
Þ
Integrating (4.15) from an initial location (denoted by the subscript ''i '') to a final
position (denoted by the subscript ''f ''), we find that
ð
Bdz
¼
0
2
2
þ
0
p
0
f
0
p
0
i
1
1
2
j
v
f
j
2
j
v
i
j
ð
4
:
16
Þ
Now, suppose an air parcel moving at constant altitude, at mid-levels, in a storm-
relative reference frame catches up with a convective storm and air flows around
the updraft, but forks to the left side (
Figure 4.3
). Outside the updraft of the
storm B
¼
0 and far upstream of the storm p
0
i
¼
0. Following an argument Kerry
Emanuel reproduced in his text, suppose that the air speeds up as it flows around
the edge of updraft such that
2
2
j
v
f
j
2
j
v
i
j
ð
4
:
17
Þ
Figure 4.3. Idealized illustration of air at mid-levels catching up with and flowing around an
updraft inside which lower values of westerly momentum have been advected upward. Air
begins at I and is decelerated as it approaches the updraft; it then speeds up as it flows around
the left side of the updraft and ends up at F.
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