Geoscience Reference
In-Depth Information
Taking the dot product of the equation in (4.11) with the differential position
vector defined by (4.12), we find that
p 0
1
Dv
=
Dt
dr ¼ J ð
2 v
v Þ E
dr þ½ð JT
v Þ T
v E
dr ¼ 0 J
dr þ Bdz
ð 4
:
13 Þ
E
E
E
Integrating (4.13) along a streamline (v), it follows that the Lamb term ½ð JT v Þ T v
is zero, because ½ð JT v Þ T v E v ¼ 0, and so
ð
ð
Þ dx þ Ð @=@
2
2
2
1
1
1
@=@
x ð
2 j v j
y ð
2 j v j
Þ dy þ
@=@
z ð
2 j v j
Þ dz
ð
ð Bdz ð 4
p 0
p 0
p 0
¼
0 ð@
=@
xdx þ@
=@
ydy þ@
=@
zdz Þþ
:
14 Þ
Since the LHS of (4.14) may be expressed as ð d ð
2
1
2 j v j
Þ , it follows that
ð d ð
Þþ 0 ð dp 0
ð Bdz ¼ 0
2
1
2 j v j
ð 4
:
15 Þ
Integrating (4.15) from an initial location (denoted by the subscript ''i '') to a final
position (denoted by the subscript ''f ''), we find that
ð Bdz ¼ 0
2
2
þ 0 p 0 f 0 p 0 i
1
1
2 j v f j
2 j v i j
ð 4
:
16 Þ
Now, suppose an air parcel moving at constant altitude, at mid-levels, in a storm-
relative reference frame catches up with a convective storm and air flows around
the updraft, but forks to the left side ( Figure 4.3 ). Outside the updraft of the
storm B ¼ 0 and far upstream of the storm p 0 i ¼ 0. Following an argument Kerry
Emanuel reproduced in his text, suppose that the air speeds up as it flows around
the edge of updraft such that
2
2
j v f j
2 j v i j
ð 4
:
17 Þ
Figure 4.3. Idealized illustration of air at mid-levels catching up with and flowing around an
updraft inside which lower values of westerly momentum have been advected upward. Air
begins at I and is decelerated as it approaches the updraft; it then speeds up as it flows around
the left side of the updraft and ends up at F.
 
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