Geoscience Reference
In-Depth Information
U
where θ is the angle between the two vectors and U and V are the magnitudes of the vectors
(Fig. A1.1). The scalar product is also known as the dot product. If U and V are parallel, then
θ = 0, cos θ = 1, and so U · V = 1. However, if U and V are perpendicular, then θ = 90 and
U · V = 0. Thus, the scalar product of two perpendicular vectors is zero. In Cartesian
coordinates ( x , y , z ), the scalar product is
V
θ
Figure A1.1.
(A1.3)
U
·
V
=
U x V x
+
U y V y
+
U z V z
As an example of a scalar product, consider a force F acting on a mass m and moving that
mass a distance d . The work done is then F
W
·
d :work is a scalar.
The vector product of two vectors U and V is written U
V or U
×
V and defined as
U V = W
(A1.4)
V
θ
where W is a vector perpendicular both to U and to V (Fig. A1.2), with magnitude
U
(A1.5)
W
=
UV sin
θ
Figure A1.2.
The vector product is also known as the cross product . The vector product of two parallel
vectors is zero since sin
θ =
0when
θ =
0. In Cartesian coordinates ( x
,
y
,
z ), the vector
product is expressed as
U V =
( U y V z
U z V y , U z V x
U x V z , U x V y
U y V x )
(A1.6)
As an example of a vector product, consider a rigid body rotating about an axis with angular
velocity (the Earth spinning about its north-south axis if you like). The velocity v of any
particle at a radial position r is then given by
(A1.7)
V
= ∧
r
Compare this with Eq. (2.3); rotation of the plates also involves the vector product.
Gradient
The gradient of a scalar T is a vector that describes the rate of change of T . The component of
grad T in any direction is the rate of change of T in that direction. Thus, the x component is
T /∂ x , the y component is T /∂ y , and the z component is T /∂ z .grad T is an abbreviation for
'the gradient of T ':
(A1.8)
grad T
≡∇ T
defines the vector operator
. The notations grad T and
T are equivalent and are used
interchangeably. In Cartesian coordinates ( x , y , z ),
T is given by
T
x
, T
y , T
(A1.9)
T
=
z
grad T is normal (perpendicular) to surfaces of constant T .Toshow this, consider the
temperature T at point ( x , y , z ). A small distance
r
=
(
x,
y,
z) away, the temperature is
T + T ,where
T
+
T
+
T
T
=
x
x
y
y
z
z
(A1.10)
=
(
T )
·
r
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