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Substituting Eq. (7.22) into Eq. (7.21) and then integrating the second time gives
A
2 k z 2
Q 0
k
T
=−
+
z + c 2
(7.23)
where c 2 is the constant of integration. However, since T
0was specified
as boundary condition (i), c 2 must equal zero. The temperature within the column
is therefore given by
=
0at z
=
A
2 k z 2
Q 0
k
T
=−
+
z
(7.24)
An alternative pair of boundary conditions could be
(i) temperature T = 0at z = 0 and
(ii) heat flow Q =− Q d at z = d .
This could, for example, be used to estimate equilibrium crustal geotherms if d
was the depth of the crust/mantle boundary and Q d was the mantle heat flow into
the base of the crust. For these boundary conditions, integrating Eq. (7.20)gives,
as before,
T
A
k
z =−
z + c 1
(7.25)
where c 1 is the constant of integration. Because
T
/∂
z
=
Q d /
k at z
=
d is
boundary condition (ii), c 1 is given by
Q d
k
Ad
k
c 1 =
+
(7.26)
Substituting Eq. (7.26) into Eq. (7.25) and then integrating again gives
Q d + Ad
k
A
2 k z 2
T
=−
+
z + c 2
(7.27)
where c 2 is the constant of integration. Because T
0was boundary
condition (i), c 2 must equal zero. The temperature in the column 0
=
0at z
=
z
d is
therefore given by
A
2 k z 2
Q d +
Ad
T
=−
+
z
(7.28)
k
Comparison of the second term in Eq. (7.24) with that in Eq. (7.28) shows that
a column of material of thickness d and radioactive heat generation A makes a
contribution to the surface heat flow of Ad . Similarly, the mantle heat flow Q d
contributes Q d z
/
k to the temperature at depth z .
7.3.2 One-layer models
Figure 7.3 illustrates how the equilibrium geotherm for a model rock column
changes when the conductivity, radioactive heat generation and basal heat flow
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