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The following basic concepts and properties are due to Schnyder [16]. For any
Schnyder wood the edges of colour i form a tree T i rooted at a i . The path from
internal vertex v to a i in T i is denoted P i ( v ).
(P1) If T i
T i +1
contains no directed cycle. In particular, any two outgoing paths from a
vertex v have no vertex in common, except for v , i.e., P i ( v )
denotes the tree in colour i with all arcs reversed, then T i− 1
T i
P j ( v )=
{
v
}
for i
= j .
The descendants of vertex v in T i , denoted D i ( v ), are the vertices that have paths
to v in T i . For any interior vertex v the three paths P i ( v ) ,i =1 , 2 , 3 partition
the triangulation into three regions R i ( v ) ,i =1 , 2 , 3,where R i ( v ) is bounded
by P i +1 ( v ) ,P i− 1 ( v ) and a i +1 a i− 1 . Schnyder proved that every triangulation T
has a Schnyder wood and that a planar drawing of T can be obtained from
coordinates that count faces inside regions:
Theorem 1 (Schnyder [15,16]). Let T be a planar triangulation on n vertices
equipped with a Schnyder wood S . Consider the map f : V ( T ) R
3 ,where
f ( a i )=(2 n− 5) e i ,where e i denotes the i -th standard basis vector in R
3 ,andfor
each interior vertex v , f ( v )=( v 1 ,v 2 ,v 3 ) ,where v i denotes the number of faces
contained inside region R i ( v ) .Then f defines a straight-line planar drawing.
Dhandapani [7] noted that the above result generalizes to weighted faces. A
weight distribution w is a function that assigns a positive weight to each internal
face such that the weights sum to 2 n
5. For any weight distribution, the above
result still holds if v i is defined as:
v i =
{
w ( f ): f
R i ( v )
}
.
(1)
We call the resulting straight-line planar drawing the weighted Schnyder drawing
obtained from w and S .
We now describe results of Brehm [5], Ossona De Mendez [14], and Felsner [11]
on the flip operation that can be used to convert any Schnyder wood to any
other. Let S be a Schnyder wood of planar triangulation T .Aflipoperateson
a cyclically oriented triangle C of T . We use the following properties of such a
triangle (proofs in the long version).
(S1) The triangle C has an edge of each colour in S .Furthermore,if C is
oriented counterclockwise then the edges along C have colours i , i
1, i +1.
(S2) If C is a separating triangle, then the restriction of S to the interior edges
of T
| C is a Schnyder wood of T
| C .
Let C = xyz be oriented counterclockwise with edges xy,yz,zx of colour
1 , 3 , 2 respectively. A clockwise flip of C alters the colours and orientations of S
as follows:
1. Edges on the cycle are reversed and colours change from i to i
1.See
triangle xyz in Figure 3.
 
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