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¢ () =
(
()
) ¢ ()
p u
DP d u d u .
This fact and induction leads to a proof of equation (11.87). The uniqueness of P
follows from the derivative formula (11.87).
Note. The term “polar form” comes from mathematics. The term “blossom” was
introduced by Ramshaw in [Rams88]. A polynomial can be recovered from its
blossom.
11.5.2.2 Example. A classical example of a blossom is the dot product function
P( u , v ) = u v in R n , which is the blossom of the length squared function p( v ) = | v | 2 .
11.5.2.3
Example.
The blossom of the cubic polynomial
() =+ +
2 2
3
pu
a
au a u
+
a u
01
3
is
(
) =+ (
)
(
) + (
)
(
) +
Pu u u
,
,
a
a
3
u
++
u
u
a
3
uu
+
uu
+
u u
a uu u
.
1
2
3
0
1
1
2
3
2
1
2
1
3
2
3
3
1
2
3
What is the point of all of this? Replacing a polynomial of degree k with a func-
tion in k variables that is linear in each variable turns out to be very useful. We shall
see that it is another example of how nonlinear problems can be solved by lineariz-
ing them. To see what is going on here we look at a simple example.
11.5.2.4
Example.
Consider the function
() =
2
pu
31
u
.
on [0,1] which has blossom
(
) =
pu u
,
3
uu
+
1
.
12
12
Suppose that we want to compute p(1/3). If D is the diagonal map D(u) = (u,u), then
p(u) = P(D(u)). See Figure 11.22. Let A , B ,...be the points as indicated in the figure.
Figure 11.22.
How blossoming linearizes maps.
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