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2
4
3
5
¼
l
0
H
DM
Dt
rate of magnetic work
done on fluid per unit
volume
ð
5
:
44
Þ
Then the energy equation Eq. (
5.43
) can be de
ned as
h
i
Du
Dt
¼
r
_
þ l
0
H
DM
Dt
¼
viscous
:
r~
q
þ
v
ð
5
:
45
Þ
By expressing the internal energy u as a function of enthalpy h and the magnetic
energy (HM) (see the Chap.
1
on thermodynamics):
u ¼ h
þ l
0
MH
ð
5
:
46
Þ
and substituting Eq. (
5.46
) into Eq. (
5.45
), we can obtain the following relation for
the energy equation:
h
i
Dh
Dt
þ l
0
D
Dt
MH
þ l
0
H
DM
¼
viscous
:
r~
Þ
¼
r
_
ð
þ
ð
5
:
47
Þ
q
v
Dt
From the relation:
dMH
ð
Þ
¼
MdH
þ
HdM
ð
5
:
48
Þ
Equation (
5.47
) can be rearranged into:
h
i
Dh
Dt
þ l
0
M
DH
¼
viscous
:
r~
Dt
¼
r
_
q
þ
v
ð
5
:
49
Þ
The total derivative of the enthalpy equals (see the Chap.
1
on thermodynamics):
dh
ð
s
;
H
Þ
¼
o
h
o
o
h
ds
þ
dH ¼ Tds
l
0
MdH
ð
5
:
50
Þ
s
H
o
H
s
Since the total derivate of the entropy equals (see the Chap.
1
on thermodynamics):
Þ
¼
o
s
o
s
c
H
T
dT
þ
o
s
ds T
;
H
ð
dT
þ
dH ¼
dH
ð
5
:
51
Þ
T
H
H
o
o
o
H
T
T
where Eq. (
5.51
) can be rewritten using the Maxwell relation:
T
¼
l
0
o
s
M
o
o
ð
5
:
52
Þ
H
T
o
H
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