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This is nonsingular at 2 (since the partial derivative with respect to y is
2 y +1
0 (mod 2)). Therefore, E has good reduction at 2. We conclude
that E has good reduction at all primes except p = 11, where it has bad
reduction. The equation y 3 + y 3 = x 3
1
x 3 is the minimal Weierstrass equation
for E .
Let's analyze the situation at 11 more closely. The polynomial in x 2 factors
as
x 2 4 x 2 +16=( x 2 +1) 2 ( x 2 +5) .
Therefore, E has multiplicative reduction at 11. The method of Section 2.10
shows that the slopes of the tangent lines at the singular point ( x 2 ,y 2 )=
(
1 , 0) are
±
2, which lie in F 11 . Therefore, E has split multiplicative reduc-
tion at 11.
We now give the full definition of the L -series of E .Foraprime p of bad
reduction, define
0if E has additive reduction at p
1if E has split multiplicative reduction at p
a p =
1if E has nonsplit multiplicative reduction at p .
The numbers a p for primes of good reduction are those given above: a p =
p +1
# E ( F p ). Then the L -function of E is the Euler product
L E ( s )=
bad p
1 − a p p −s 1
1 − a p p −s + p 1 2 s 1 .
good p
The estimate |a p | < 2 p easily implies that the product converges for ( s ) >
3 / 2 (see Exercise 14.3).
Each good factor can be expanded in the form
a p p −s + p 1 2 s ) 1 =1+ a p p −s + a p 2 p 2 s +
(1
···
,
where the a p on the left equals the a p on the right (so this is not bad notation)
and
a p 2 = a p
p.
(14.1)
The product over all p yields an expression
L E ( s )=
a n n −s .
n =1
If n = j p e j
,then
j
a n =
j
a p e j
j
.
(14.2)
 
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