Cryptography Reference
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Therefore, there is a constant C such that
u ) e u + 2 u 2
3
|
(1
1
|≤
C
|
u
|
for u near 0. In particular, this inequality holds when u = z/ω for |ω| su-
ciently large and z in a compact set. Recall that if a sum |a n | converges,
then the product (1+ a n ) converges. Moreover, if (1+ a n ) =0forall n ,then
the product is nonzero. Since |z/ω|
3 converges by Lemma 9.4 with k =3,
the product defining σ ( z ) converges uniformly on compact sets. Therefore,
σ ( z ) is analytic. This proves (1). Part (2) follows since the product of the
factors, omitting one ω , is nonzero at z = ω .
To prove (3), differentiate the logarithm of the product for σ ( z )toobtain
1
z − ω +
ω 2 .
z +
ω∈L
ω =0
dz log σ ( z )= 1
d
1
ω +
z
Taking one more derivative yields the sum for
( z ). This proves (3).
Let ω
L .Since
d 2
dz 2 log σ ( z + ω )
=0 ,
σ ( z )
there are constants a = a ω and b = b ω such that
log σ ( z + ω )
σ ( z )
= az + b.
Exponentiating yields (4). We can restrict z in the above to lie in a small re-
gion in order to avoid potential complications with branches of the logarithm.
Then (4) holds in this small region, and therefore for all z
C , by uniqueness
of analytic continuation.
We can now state exactly when a divisor is a divisor of a function. The
following is a special case of what is known as the Abel-Jacobi theorem ,
which states when a divisor on a Riemann surface, or on an algebraic curve,
is the divisor of a function.
THEOREM 9.6
Let D = n i [ w i ] be a divisor. T hen D isthe divisor of a function ifand
onlyif deg( D )=0 and n i w i ∈ L .
PROOF
Parts (3) and (4) of Theorem 9.1 are precisely the statements
that if D is the divisor of a function then deg( D )=0and n i w i
L .
Conversely, suppose deg( D )=0and n i w i =
L .Let
σ ( z − )
i
σ ( z )
w i ) n i .
f ( z )=
σ ( z
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