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Fig. 6.
Experiment 2: numerical solution at several time moments (North pole view)
where
∂t
=
c
1
cos
ϕ
θ
2
γ
cos
ξ
tan
κ
2
ϕ
cos
γt
cos
2
t −
sin
ξ
sin 2
t
,
∂T
∂λ
=
c
1
ω
cos
ϕ
cos
2
t
cos
ξ,
∂
2
T
∂λ
2
=
−c
1
ω
2
cos
ϕ
cos
2
t
sin
ξ,
∂T
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