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56.5255
56.5254
56.5253
56.5252
56.5251
56.525
56.5249
56.5248
56.5247
56.5246
56.5245
0
2
4
6
8
10
Time
Fig. 4. Experiment 1: graph of the L 2 -norm of the solution in time
Fig. 5. Experiment 2: the profile of the diffusion factor μ (North pole view). The colour map
ranges from white (maximum) to black (minimum).
where
ξ ≡ ω ( λ − ϑ 1 tan κ 1 ϕ )+ ϑ 2 tan κ 2 ϕ sin γt .
(33)
In order for (32) to be the solution to (1), the sources must be
α ∂T
∂λ
2
μT α− 1
R cos ϕ
+ T 2 T
∂λ 2
∂T
∂t
1
R cos ϕ
f ( λ, ϕ, t )=
2
T 2 T
+ α ∂T
∂ϕ
+ cos ϕ
R
∂ϕ 2 tan ϕ ∂T
,
(34)
∂ϕ
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