Digital Signal Processing Reference
In-Depth Information
• The probability that more than one zero crossing in an infinitesimal interval
appear is infinitely small compared to the probability of only one zero crossing.
•
If a zero crossing occurs in the interval
t
, then there is an equal probability of its
occurring in any of the infinitesimal intervals d
t
, in which the interval
t
is
divided.
Find the autocorrelation function and demonstrate its properties.
Solution
According to the aforementioned properties of the given process, we can
conclude that the process is a Poisson process (see Sect.
5.7
).
Therefore, the number of the zero crossing in a given interval
t
is described by
the Poisson formula:
k
Pfk
zero crossing in
tg¼
ð
lt
Þ
e
lt
;
(6.71)
k
!
where
l
is an average number of zero crossing in a unit of time.
Random variables in time instants
t
1
¼
t and
t
2
¼t
+
t
, are denoted as
X
1
and
X
2
,
respectively, as shown in Fig.
6.9
. The autocorrelation function is:
R
XX
ðtÞ¼X
1
X
2
¼
X
X
2
2
x
1
i
x
2
j
PfðX
1
¼ x
1
i
Þ\ðX
2
¼ x
2
j
Þ
;
tg:
(6.72)
i¼
1
j¼
1
The joint probability from (
6.72
) can be expressed using the conditional proba-
bility, as shown in the following equation:
PfðX
1
¼ x
1
i
Þ\ðX
2
¼ x
2
j
Þ
;
t; t þ tg
¼ PfX
1
¼ x
1
i
;
tgPfX
2
¼ x
2
j
;
t þ tjX
1
¼ x
1
i
;
tg:
(6.73)
The random variables
X
1
and
X
2
have an equal probability of taking the values
U
and
U
:
PfX
1
¼ Ug¼PfX
1
¼Ug¼PfX
2
¼ Ug¼PfX
2
¼Ug¼
1
=
2
:
(6.74)
We find the conditional probabilities by taking into account the following
considerations.
The amplitudes in time instants
t
and
t
+
t
, will be the same if there is either no
zero crossing or an even number of zero crossing in the time interval
t
:
PfX
2
¼ UjX
1
¼ U
;
tg¼PfX
2
¼UjX
1
¼U
;
tg
¼
1
k¼
0
(6.75)
P
X
ðk
;
tÞ;
;
2
;
4
;
...
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