Digital Signal Processing Reference
In-Depth Information
Exercise 4.11
The joint density function of the normal random variables
X
1
and
X
2
is given as:
h
i
2
x
2
225
ðx
1
5
Þ
ð
x
1
5
Þ
x
2
150
e
1
:
5
1
300
p
þ
100
f
X
1
X
2
ðx
1
; x
2
Þ¼
p
:
(4.189)
0
:
75
Find the correlation coefficient and the mean value of the variable
X ¼ aX
1
þ bX
2
:
(4.190)
Answer
Comparing the general expression (
4.124
) and (
4.189
), we have:
5
¼
2
ð
1
r
2
1
:
Þ
and
r ¼
0
:
5
:
(4.191)
The mean values of the variables
X
1
and
X
2
are 5 and zero, respectively. From
(
4.190
), we have:
EfXg¼afX
1
gþbEfX
2
g¼
5
a þ
0
¼
5
a:
(4.192)
Exercise 4.12
Three independent normal random variables have the following
parameters:
s
i
¼
4
m
i
¼
0
;
;
i ¼
1
;
2
;
3
:
(4.193)
Find the coefficient of correlation for variables
Y
1
and
Y
2
if
Y
1
¼ X
1
þ X
2
;
Y
2
¼ X
2
X
3
:
(4.194)
Answer
The random variables
Y
1
and
Y
2
are the sums of normal random variables
and consequently, they are also normal with the parameters,
EfY
1
g¼EfX
1
gþEfX
2
g¼
0
;
EfY
2
g¼EfX
2
gEfX
3
g¼
0
;
s
Y
1
¼ s
1
þ s
2
¼
8
;
s
2
Y
2
¼ s
2
þ s
3
¼
8
:
(4.195)
Knowing that the variables
X
i
are independent, it follows that
X
i
X
j
¼ X
i
X
j
¼
0
;
i
6¼ j:
(4.196)
The correlation coefficient is:
X
2
8
¼
s
2
8
¼
Y
1
Y
2
Y
1
Y
2
s
Y
1
s
Y
2
¼
ð
X
1
þ
X
2
Þð
X
2
X
3
Þ
8
4
8
¼
0
r ¼
¼
:
5
:
(4.197)
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