Digital Signal Processing Reference
In-Depth Information
Exercise 4.11 The joint density function of the normal random variables X 1 and X 2
is given as:
h
i
2
x 2
225
ðx 1 5 Þ
ð x 1 5 Þ x 2
150
e 1 : 5
1
300 p
þ
100
f X 1 X 2 ðx 1 ; x 2 Þ¼
p
:
(4.189)
0
:
75
Find the correlation coefficient and the mean value of the variable
X ¼ aX 1 þ bX 2 :
(4.190)
Answer Comparing the general expression ( 4.124 ) and ( 4.189 ), we have:
5 ¼ 2 ð 1 r 2
1
:
Þ
and r ¼ 0
:
5
:
(4.191)
The mean values of the variables X 1 and X 2 are 5 and zero, respectively. From
( 4.190 ), we have:
EfXg¼afX 1 gþbEfX 2 5 a þ 0 ¼ 5 a:
(4.192)
Exercise 4.12 Three independent normal random variables have the following
parameters:
s i ¼ 4
m i ¼ 0
;
;
i ¼ 1
;
2
;
3
:
(4.193)
Find the coefficient of correlation for variables Y 1 and Y 2 if
Y 1 ¼ X 1 þ X 2 ;
Y 2 ¼ X 2 X 3 :
(4.194)
Answer The random variables Y 1 and Y 2 are the sums of normal random variables
and consequently, they are also normal with the parameters,
EfY 1 g¼EfX 1 gþEfX 2 0
;
EfY 2 g¼EfX 2 gEfX 3 0
;
s Y 1 ¼ s 1 þ s 2 ¼ 8
;
s 2
Y 2 ¼ s 2 þ s 3 ¼ 8
:
(4.195)
Knowing that the variables X i are independent, it follows that
X i X j ¼ X i X j ¼ 0
;
i
6¼ j:
(4.196)
The correlation coefficient is:
X 2
8 ¼
s 2
8 ¼
Y 1 Y 2 Y 1 Y 2
s Y 1 s Y 2
¼ ð X 1 þ X 2 Þð X 2 X 3 Þ
8
4
8 ¼ 0
r ¼
¼
:
5
:
(4.197)
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