Digital Signal Processing Reference
In-Depth Information
Exercise 4.10 The independent normal random variables X 1 and X 2 are related
with the random variable Y , as shown in Fig. 4.25 . Find the variance for the random
variable Y if the parameters of the variables X 1 and X 2 are m 1 ¼ 2, s 1 ¼ 4 and
m 2 ¼ 0, s 2 ¼ 5, respectively. (Use Q function.)
Answer The random variable X is a sum of independent normal random variables
and has the following parameters:
s 2
¼ s 1 þ s 2 ¼ 9
;
m ¼ m 1 þ m 2 ¼ 2
:
The variable X is also a normal random variable, X¼ N (2, 9).
The output random variable Y is a discrete random variable with the discrete
values 2 and 0. The corresponding probabilities are:
PfY ¼ 2 g¼PfX<
8 g ;
PfY ¼ 0 g¼PfX>
8 g:
(4.185)
Using ( 4.53 ), we have:
PfY ¼ 2 g¼PfX 8 1 PfX>
8 1 QðkÞ
¼ 1 2 Þ;
j
8 2
j
¼ 1 Q
3
PfY ¼ 0 1 PfY ¼ 2 g¼Qð 2 Þ:
(4.186)
Using ( 4.186 ), the variance of the variable Y is obtained as:
Y 2
s Y ¼ Y 2
2
2
¼ 4 ð 1 2 ÞÞ ½ 2 ð 1 2 Þ
¼ 4 2 Þ 4 ½Qð 2 Þ
:
(4.187)
The function Q is related to the erf function as shown in Table 4.1 , resulting in:
2
4
2
2
2
4
2
2
2
s 2
p
p
Y ¼
1 erf
1 erf
¼ 0
:
091 0
:
0041 ¼ 0
:
0869
:
(4.188)
Fig. 4.25 Random variables X 1 , X 2 , and Y
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