Digital Signal Processing Reference
In-Depth Information
Exercise 4.10
The independent normal random variables
X
1
and
X
2
are related
with the random variable
Y
, as shown in Fig.
4.25
. Find the variance for the random
variable
Y
if the parameters of the variables
X
1
and
X
2
are
m
1
¼
2,
s
1
¼
4 and
m
2
¼
0,
s
2
¼
5, respectively. (Use Q function.)
Answer
The random variable
X
is a sum of independent normal random variables
and has the following parameters:
s
2
¼ s
1
þ s
2
¼
9
;
m ¼ m
1
þ m
2
¼
2
:
The variable
X
is also a normal random variable,
X¼ N
(2, 9).
The output random variable
Y
is a discrete random variable with the discrete
values 2 and 0. The corresponding probabilities are:
PfY ¼
2
g¼PfX<
8
g
;
PfY ¼
0
g¼PfX>
8
g:
(4.185)
Using (
4.53
), we have:
PfY ¼
2
g¼PfX
8
g¼
1
PfX>
8
g¼
1
QðkÞ
¼
1
Qð
2
Þ;
j
8
2
j
¼
1
Q
3
PfY ¼
0
g¼
1
PfY ¼
2
g¼Qð
2
Þ:
(4.186)
Using (
4.186
), the variance of the variable
Y
is obtained as:
Y
2
s
Y
¼ Y
2
2
2
¼
4
ð
1
Qð
2
ÞÞ ½
2
ð
1
Qð
2
Þ
¼
4
Qð
2
Þ
4
½Qð
2
Þ
:
(4.187)
The function
Q
is related to the erf function as shown in Table
4.1
, resulting in:
2
4
2
2
2
4
2
2
2
s
2
p
p
Y
¼
1
erf
1
erf
¼
0
:
091
0
:
0041
¼
0
:
0869
:
(4.188)
Fig. 4.25
Random variables
X
1
,
X
2
, and
Y
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