Civil Engineering Reference
In-Depth Information
2
a
d
a
d
−
1.974
+
2.77
×
0.1215
=
0
f
f
a
d
1.974
1.974
2
42.770.1215
2
−
− ×
×
=
=
0.1887
f
a
=
113.25 mm
c
=
135.95 mm
cd
c
−
400
200,000
−
3
−
3
ε=
0.003
=
1.72
×
10
<
= ×
210
oyielding N.G.
s
6
M
fbd
d
d
×
×× ×
500
10
535
600
u
Q
=
φ
+Ψ−=
Q
+
0.1524 0.85
−
2
1
f
2
2
0.930
350
600
cf
f
=
0.1406
600
d
d
d
d
400
350
600
30
535
600
58
600
QQ
=−ρ
Ψ −
=
0.1406
−
×
×
0.85
−
2
2
s
f
f
535
×
c
f
f
=
0.1119
3
2
a
d
a
d
a
d
0.833
58
×
(
)
−
2
+
2.770.1119
×
+
2.77 0.1406
−
0.1119
×
=
0
600
f
f
f
3
2
a
d
a
d
a
d
−
3
−
2
+
0.31
+× =
6.4
10
0
f
f
f
a
d
f
= →
0.1893
By finding thesmallest positiveroot using Excel Goal Seek
113.58
0.833
a
=
113.58 mm
c
=
=
136.35 mm
0.003
136.35 58
136.35
−
−
3
ε=
=
1.724
×
10
s
−
3
f
=
200000
×
1.724
×
10
=
344.78 MPa
s
0.003
600 136.35
136.35
−
ε=
−= ≈
00.0102
0.009944
fe
30
ε=
0.41
=
0.009944
fd
2
×
150,000
×
0.17
f
fe
=
150,000
×
0.0102
=
1, 530 MPa
0.003
535 136.35
136.35
−
0.00877
0.005
ε=
=
>
s
so
0.9
φ=
f
f
f
f
a
d
f
f
c
fe
y
fe
s
fe
ρ=
0.85
−ρ
+ρ
f
s
s
30
1530
113.58
535
2400
350
400
1530
400
350
344.78
1530
−
4
=
0.85
×
×
−
×
+
×
=
6.688
×
10
×
535
×
535
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