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or
CA ¼ K 0 1 K CO 2 pCO 2
H fg þ 2 K 0 1 K 0 2 K CO 2 pCO 2
ð 4 : 12 Þ
H f 2
This equation can be rearranged to give the following quadratic
expression that can be solved for the pH
CA H f 2 K 0 1 K CO 2 pCO 2 H fg 2K 0 1 K 0 2 K CO 2 pCO 2 ¼ 0
Worked Example 1
For seawater (35 psu, 15 1C) with an alkalinity of 2.30 meq l 1 and in
equilibrium with atmospheric CO 2 ¼ 3.65 10 4 atm, calculate (i)
the pH and (ii) the speciation of carbonic acid.
(i) pH calculation
Data, including constants from Table 4 are K CO2 ¼ 10 1.41 , K 0 1 ¼
10 6.05 , K 0 2 ¼ 10 9.23 ,CA ¼ 2.30 10 3 , pCO 2 ¼ 3.65 10 4
The pH is obtained from the calculation of {H 1 } using the above
quadratic equation. Thus
H fg¼ b þ
p
b 2 4ac
2a
where
a ¼ CA
¼ 2 : 30 10 3
b ¼ K 1 K CO2 pCO 2
¼ 10 6 : 5 10 1 : 41 10 3 : 46
¼ 1 : 20 10 11
c ¼ 2K 1 K 2 K CO2 pCO 2
¼ 210 6 : 05 10 9 : 23 10 1 : 41 10 3 : 46
¼ 1 : 42 10 20
Giving {H 1 } ¼ 6.22 10 9 and pH ¼ 8.21.
(ii) Carbonic acid speciation calculations
Knowing the pH, each of the three major species (H 2 CO 3 , HCO 3 ,
CO 3 2 ) can be calculated as a fraction (or percentage) of the P CO 2 .
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