Geology Reference
In-Depth Information
1.4.7 The Papkovich-Neuber solution
Other forms of solutions to the Navier equation can be developed. Using the dimen-
sionless Poisson's ratio σ (1.255), it can be recast in the form
1
F
μ .
2 u
+
(
∇·
u )
=−
(1.323)
1
2 L , it follows that
2 (
Since
∇·
u
=∇
(
∇·
u )
=∇
L ), and
2 u
L
1
F
μ .
+
=−
(1.324)
1
Writing the vector quantity in square brackets as Φ /2μ,wehave
2 Φ
=−
2 F ,
(1.325)
with
1
1
Φ
=
u
+
L .
(1.326)
1
Taking the divergence of both sides of the latter relation gives
1
∇·
2 (1
σ)
2 L .
Φ
=
(1.327)
1
Using the vector identity
2 ( R
2 Φ
·
Φ )
=
R
·∇
+
2 (
∇·
Φ ),
(1.328)
and relation (1.325), we obtain
2
F
1
1
σ
2 ( R
2 L .
∇· Φ =
· Φ )
+
2 R
·
=
(1.329)
1
Thus,
2 2 μ
1
Φ
1
1
L
σ ) R
·
=
σ ) R
·
F .
(1.330)
4 ( 1
2 ( 1
Denoting the scalar in square brackets by B ,
1
2 B =
σ) R
·
F ,
(1.331)
2 (1
and
B
Φ
1
1
L
=
+
σ) R
·
.
(1.332)
4 (1
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