Civil Engineering Reference
In-Depth Information
Table 6.1
Calculation results of panel M3
Calculated values
Variables
Point 1 (first yielding)
Point 2 (peak point)
Point 3 (descending)
ε
2
selected
−
0.000082
−
0.00027
−
0.00300
ε
1
last assumed
0.002254
0.010181
0.027416
γ
12
last assumed
0.00094
0.00689
0.01672
ε
0.000618
0.00151
0.003848
ε
t
0.001554
0.00835
0.020568
ν
12
1.52
1.90
1.90
¯
ε
1
0.002129
0.009668
0.021716
¯
ε
2
−
0.000082
−
0.00027
−
0.00300
¯
ε
0.000556
0.001253
0.000998
¯
ε
t
0.001492
0.008144
0.017718
β
(degrees)
10.9
16.7
14.4
ζ
0.335
0.115
0.107
σ
2
(MPa)
−
3.12
−
5.54
−
4.73
1
(MPa)
σ
0.579
0.316
0.229
c
12
(MPa)
τ
0.741
1.932
1.361
f
(MPa)
118.2
266.6
212.2
f
t
(MPa)
278.8
355.3
465.5
(
ρ
f
+
ρ
t
f
t
)
1
2.540
5.207
4.492
(
ρ
f
−
ρ
t
f
t
)
1
1.480
3.857
2.723
(
ρ
f
+
ρ
t
f
t
)
2
2.541
5.227
4.496
(
ρ
f
−
ρ
t
f
t
)
2
1.481
3.863
2.723
τ
t
(MPa)
1.849
2.929
2.477
γ
t
0.002336
0.010451
0.030416
α
1
−
γ
1
2
ε
1
cos
2
ε
2
sin
2
Equation 11
ε
=
¯
¯
α
1
+
¯
2sin
α
1
cos
α
1
=
0
.
021716(0
.
5)
+
(
−
0
.
00300)(0
.
5)
−
(0
.
01672)(0
.
5)
=
0
.
000998
Notice that the uniaxial strain ¯
ε
=
0.000998 is much smaller than the biaxial strain
ε
=
0.003848 due to Poisson effect.
α
1
+
γ
1
2
ε
t
=
ε
1
sin
2
α
1
+
ε
2
cos
2
α
1
cos
α
1
Equation 12
¯
¯
¯
2sin
=
0
.
021716(0
.
5)
+
(
−
0
.
00300)(0
.
5)
+
(0
.
01672)(0
.
5)
=
0
.
017718
2
tan
−
1
2
tan
−
1
γ
12
.
1
1
0
01672
40
◦
Equation
β
=
=
=
14
.
15
ε
1
−
ε
2
)
.
+
.
(
(0
027416
0
00300)
5
9
1
8
f
c
≤
.
1
|
β
|
24
◦
Equation
14
ζ
=
0
.
√
1
−
+
400¯
ε
1
9
1
40
◦
24
◦
8
√
48
5
.
1
14
.
=
1
≤
0
.
√
1
−
+
400(0
.
021716)
.
=
(0
.
8363) (0
.
3213) (0
.
400)
=
0
.
1075