Biomedical Engineering Reference
In-Depth Information
Refraction at second lens :
=
L
L
+
F
(1.00)(100)
=
L
+
1.00 D
10.00 cm
=
L
10.00 D
+
1.00 D
=
L
9.00 D
n
=
L
l
(1.00)(100)
l
=
9.00 D
=
l
11.11 cm
The virtual image is located 11.11 cm to the left of the second lens.
(b) Total lateral magnification
=
( M L for first lens)( M L for second lens)
10.00 D
3.33 D
Total lateral magnification
=
13.33 D
9.00 D
Total lateral magnification
=
+
0.28
×
(45.00 mm)(
12.60 mm
(c) Since the final image is formed by diverging light rays, it is virtual.
(d) The final virtual image is erect. This is indicated by the positive sign that
is given for the total magnification.
+
0.28
×
)
=
+
CHAPTER 6
Thick Lenses
1. (a) This is the same lens as in Problem 1 of Chapter 5. We have already calcu-
lated the following:
F 1
=
+
10.40 D
F 2
=
+
20.80 D
Equivalent power :
t
F e
=
F 1 +
F 2
F 1 F 2
0.030 m
F e
=
10.40 D
+
20.80 D
(
+
10.40 D)(
+
20.80 D)
1.52
F e
= +
26.93 D
 
 
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