Biomedical Engineering Reference
In-Depth Information
n
f
′
5. (a)
F
=
(100)(1.52)
f
+
10.00 D
=
′
′
f
=
+15
.2 cm
F
′
is 15.2 cm to the right of the converging surface.
n
f
F
= −
(100)(1.00)
f
+
10.00 D
= −
f
=
−10
.0 cm
F
is 10.0 cm to the left of the converging surface
n
−
n
′
F
=
r
1.52
−
1.00
+
10.00
=
r
r
=
+
0.052 m or
+
5.2 cm
The center of curvature is 5.2 cm to the right of the surface.
(b) Image distance is about 30.4 cm to the right of the surface. The image
height is about 2.0 cm.
(c) The magnification is
.
(d) The image is inverted. Because it is formed by converging light rays that
could be focused onto a screen, it is real.
−
2.0 cm/
+
2.0 cm
≈
−
1.0
×
6. (a) The image appears closer to the surface.
(b) The diverging light rays that are emitted by the rock are further diverged
at the surface of the pond (at the water-air interface). The rays appear to
come from a point that is less than 3.0 m from the surface. Because the
image is formed by diverging light rays, it is virtual (see Fig. 3-8).
CHAPTER 3
The Vergence Relationship
n
−
n
′
1. (a)
F
=
r
1.586
−
1.00
−
10.00
=
r
r
=
−
0.059 m or
−
5.9 cm
