Graphics Reference
In-Depth Information
Let's illustrate Eq. (3.1) in a 3D context, as shown in Fig. 3.2.
Let
t
point to T 120
and
v
=−
i
−
2
j
+
2
k
Therefore,
1
3
v
ˆ
=
−
i
−
2
j
+
2
k
Y
T
t
λ
v
ˆ
O
Z
p
X
P
Figure 3.2.
The vector equation is
p
=
t
+
v
ˆ
When
=
0
x
=
1y
=
2 and z
=
0
and when
=
1
=
−
1
3
=
2
3
x
1
y
=
2
−
2
3
=
1
3
2
3
2
3
z
=
0
+
=
Thus,
3
1
3
3
is a point one unit along
ˆ
v
from T. Similarly, by changing the value and sign
of , we can move forward and backward along the 3D line.
