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B.11.13. Lemma. If f Πk[[X]] has a nonzero constant term (equivalently, ord(f) =
0), then there exists a g Πk[[X]] with fg = 1.
Proof. Simply write out the series expansions for f and g and use the equation
fg = 1 to solve for the series coefficients of g in terms of those of f.
B.11.14. Theorem.
The units of k[[X]] are the elements f with ord(f) = 0.
Proof. Lemma B.11.13 proved half of the theorem. One still needs to show that every
unit has a nonzero constant term. This is left as an easy exercise for the reader.
B.11.15. Theorem.
Every nonzero element f in k((X)) can be written uniquely in
the form
1
(
)
2
f
=
aaXaX
+
+
+
... ,
0
1
2
n
X
where a i Œ k and a 0 π 0.
Proof.
See [Walk50].
Theorem B.11.15 leads to a definition of order that extends the one for formal
power series.
Definition.
The integer n in Theorem B.11.15 is called the order of f and is denoted
by ord(f).
g is a homomor-
phism of R[[X]] into itself. We can strengthen this in the case where R is field.
Theorem B.7.5 can be interpreted as saying that the map f Æ f
B.11.16. Theorem.
If f, g Œ k[[X]], where ord(g) = 1, then the map f Æ f
g is an
order-preserving isomorphism of k[[X]], that is,
(1) ord(f) = ord(f
g).
(2) There is a g¢Œk[[X]] with ord(g¢) = 1, so that f = (f
g)
g¢ for all f Œ k[[X]].
Proof.
See [Walk50].
B.12
Algebras
Definition.
A ring A with unity that is a vector space over a field k and that satisfies
() = () =
()
u ab
ua b
a ub
,
for all
u
Œ
k a b
,
,
Œ
A
,
is called an algebra over k . If A is also a skew ring, then A is called a division algebra .
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