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n
-
1
n
n: MR
Æ
defined by
() =
n pn p
(8.10)
is a nonzero normal vector field for M n-1 .
Conversely, suppose that
n
-
1
n
n: MR
Æ
is a nonzero normal vector field for M n-1 . For each p ΠM , choose an ordered basis
( v 1 , v 2 ,..., v n-1 ) of T p so that ( v 1 , v 2 ,..., v n-1 ,n( p )) induces the standard orientation of
R n . The map
Æ [
]
pvv
,
,..., n
v
(8.11)
12
-
1
will define an orientation of M n-1 .
It follows from Theorem 8.5.1, that we can define an orientation on an orientable
(n - 1)-dimensional manifold M n-1 in R n simply by defining a nonzero normal vector
field. This is typically the way one does it. Conversely, if a manifold is oriented, then
the given orientation defines a unique unit normal vector field on it.
8.5.2. Example.
The normal vector field
2
3
n: SR
Æ
defined by n( p ) = p shows that the unit sphere S 2
is orientable and defines the stan-
dard orientation of it.
Definition. Let F : U Æ M n-1 be a regular parameterization of an (n - 1)-dimensional
submanifold M n-1 in R n . If s is an orientation of M n-1 , then the unit normal
vector field of M n-1 described in the proof of Theorem 8.5.1 and defined by equation
(8.10) is called the normal vector field of M n -1 in R n induced by s. If s is the standard
orientation of M n-1 induced by F, then that normal vector field is called the standard
normal vector field of M n -1 induced by F.
Note. If an orientable submanifold M n-1 of R n is closed (without boundary) and
bounded, like for example the unit sphere in R 3 , then it divides space into bounded
and unbounded parts and it makes sense to talk about “inward” and “outward” point-
ing normals for it.
Next, we address two related natural questions. First, we know that every compact
connected differentiable manifold is a pseudomanifold (Theorem 8.3.3). Therefore, it
is reasonable to ask whether the notion of orientable defined in this section is com-
patible with that given in Section 7.5. The second question is whether there are some
simple criteria for determining the orientability of a manifold, since one certainly does
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