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inductively by
n
sd
=
zero map for n
,
<
0
,
#
0
()
sd
=
identity map of C
K
,
0
#
q
n
n
-
1
sd
=
sd
o
sd
,
for n
>
0
.
#
q
#
#
The maps sd #q induce homomorphisms (actually isomorphisms)
(
)
n
() Æ
n
()
sd
* :
H
K
H
sd
K
.
q
q
We are now ready to show how continuous maps induce homomorphisms on
homology groups. Let K and L be simplicial complexes and let
fK L
:
Æ
be a continuous map. The Simplicial Approximation Theorem implies that there is an
n ≥ 0, such that f admits a simplicial approximation
n () Æ
j :
sd
K
L
.
Definition.
The homomorphism
() Æ
()
f
:
HK HL
*
q
q
q
defined by
n
f
=j
o
sd
*
q
*
q
*
is called the homomorphism induced on the qth homology group by the continuous
map f.
7.2.2.10. Lemma.
(1) f *q is a well-defined homomorphism.
(2) If K = L and f = 1 K , then f *q is the identity homomorphism.
(3) If M is a simplicial complex and g : ΩLΩÆ ΩMΩ is a continuous map, then
(g ° f) *q = g *q ° f *q .
Proof.
See [AgoM76].
7.2.2.11. Theorem. Let K and L be simplicial complexes and suppose that f,
g:ΩKΩÆΩLΩ are continuous maps that are homotopic. Then f *q = g *q :H q (K) Æ H q (L)
for all q.
Proof.
See [AgoM76].
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