Exception Handling - Java - page 517

try
{
System.out.println("Enter a whole number:");
number = keyboard.nextInt();
done = true ;
}
catch (InputMismatchException e)
{
keyboard.nextLine();
System.out.println(
"Not a correctly written whole number.");
System.out.println("Try again.");
}
}

return number;
}

public static void main(String[] args)
{
Scanner keyboardArg = new Scanner(System.in);
int number = getInt(keyboardArg);
System.out.println("You entered " + number);
}
}

Programming Projects
Many of these Programming Projects can be solved using AW's CodeMate.
To access these please go to: www.aw-bc.com/codemate .

1. Write a program that calculates the average of N integers. The program should

prompt the user to enter the value for N and then afterward must enter all N
numbers. If the user enters a non-positive value for N, then an exception should
be thrown (and caught) with the message “ N must be positive.” If there is any
exception as the user is entering the N numbers, an error message should be dis-
played and the user prompted to enter the number again.

2. Here is a snippet of code that inputs two integers and divides them:

Scanner scan = new Scanner(System.in);
int n1, n2;
double r;

n1 = scan.nextInt();
n2 = scan.nextInt();
r = ( double ) n1 / n2;