Java Reference
In-Depth Information
Display 9.6
Demonstration of How to Use
BadNumberException
1
import
java.util.Scanner;
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public class
BadNumberExceptionDemo
3{
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public static void
main(String[] args)
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{
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try
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{
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Scanner keyboard =
new
Scanner(System.in);
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System.out.println("Enter one of the numbers 42 and 24:");
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int
inputNumber = keyboard.nextInt();
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if
((inputNumber != 42) && (inputNumber != 24))
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throw new
BadNumberException(inputNumber);
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System.out.println("Thank you for entering " + inputNumber);
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}
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catch
(BadNumberException e)
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{
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System.out.println(e.getBadNumber() +
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" is not what I asked for.");
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}
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System.out.println("End of program.");
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}
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}
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Sample Dialogue 1
Enter one of the numbers 42 and 24:
42
Thank you for entering 42
End of program.
Sample Dialogue 2
Enter one of the numbers 42 and 24:
44
44 is not what I asked for.
End of program.
