Environmental Engineering Reference
In-Depth Information
ˆμ ∂ˆ
2
ˆ ∇· ˆ)
dr
=
dS
μ |∇ ˆ |
dr
,
n
D
D
D
1
2
ˆ ∇· ˆ s dr
=
ˆˆ s ·
n dS
.
D
D
S + ,
S
Finally, dividing each integral over
D into the four integrals over S T ,
and S B , and applying the conditions ( 2.6 )-( 2.9 ) and ( 2.12 ), we get
2 dr
2
2 k
(
ˆ,ˆ) =
˃ˆ
+
μ |∇ ˆ |
+
S T ʶˆ
·
A
dr
n dS
D
D
n dS
1
2
2 dS
2 dS
2 k
2 k
+
U n ˆ
U n ˆ
+
v s ˆ
·
v s ˆ
·
n dS
S +
S
S T
S B
(2.15)
0in S , k
Since U n
<
·
n
>
0at S T and k
·
n
<
0at S B ,Eq.( 2.15 ) can be
rewritten as
2 dr
2 dr
2 k
μ | ˆ |
(
A
ˆ,ˆ) =
˃ˆ
+
+
S T ʶˆ
·
n dS
D
D
1
2
2 dS
2
|
U n | ˆ
|
|
+
+
v s ˆ
k
·
n
dS
.
S +
S
S T
S B
Thus, operator A is positive semidefinite:
0.
Taking the inner product of every term of Eq. ( 2.4 ) with
(
A
ˆ,ˆ)
ˆ
we obtain
∂ˆ
N
t
= (
f
,ˆ) (
A
ˆ,ˆ),
f
(
r
,
t
) =
Q i (
t
)ʴ(
r
r i ).
i
=
1
Using the condition
(
A
ˆ,ˆ)
0 and the Schwarz inequality [ 17 ], the last equation
implies the inequality
ˆ, ∂ˆ
ˆ
f
,
ˆ =
(ˆ, ˆ).
t
Further,
ˆ, ∂ˆ
1
2
2
=
t ˆ
= ˆ
t ˆ
t
 
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