Biomedical Engineering Reference
In-Depth Information
ε = ξ
η
1
Lemma 6.1 (ii) with z 0 =
0,
yields the asserted inequality.
2
ξ 2
Lemma 6.4. If
w
(
t
) η
for 0
t
< Λ
(29)
for some
η >
0 ,then
i
(
t
)
c
η
for t 0
t
< Λ ,
(30)
where c is a positive constant independent of
η
, and
ln 2
1
μ +
1
γ + μ
t 0
=
1 +
.
(31)
2
α
(
)
Proof. From the equation for s
t
,Eq.( 17a ),
d s
d t +( μ +
)
μ ,
2
α
s
2
so that, by Lemma 6.1 (ii) with z 0 =
0,
ε = μ /
2
( μ +
2
α 2 )
,
μ
s
(
t
)
if t 0
t
< Λ ,
(32)
2
( μ +
2
α 2 )
where
ln 2
μ +
2 .
Substituting Eqs. ( 28 )and( 32 ) into Eq. ( 17b ), we get
t 0 =
2
α
d i
d t +( γ + μ )
α
μη
1
i
α 1 ws
α 2 ) .
2
( μ +
2
Applying once more Lemma 6.1 (ii) with z 0 =
0and
α
μη
1
ε =
α 2 ) ,
4
( γ + μ )( μ +
2
we obtain the inequality ( 30 )for t 0
t
< Λ
with t 0 as in Eq. ( 31 ).
Lemma 6.5. Set B
= γ + μ + ξ 2 .Then
e B ( t τ ) ,
e B ( t τ )
i
(
t
)
i
( τ )
w
(
t
)
w
( τ )
for all 0
< τ <
t
<
.
Indeed, this follows from the inequalities
d i
d t ≥− ( γ + μ )
d w
d t ≥− ξ
i
,
w
.
 
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