Biomedical Engineering Reference
In-Depth Information
ε
=
ξ
η
1
Lemma
6.1
(ii) with
z
0
=
0,
yields the asserted inequality.
2
ξ
2
Lemma 6.4.
If
w
(
t
)
≥
η
for 0
≤
t
<
Λ
(29)
for some
η
>
0
,then
i
(
t
)
≥
c
η
for
t
0
≤
t
<
Λ
,
(30)
where c is a positive constant independent of
η
, and
ln 2
1
μ
+
1
γ
+
μ
t
0
=
1
+
.
(31)
2
α
(
)
Proof.
From the equation for
s
t
,Eq.(
17a
),
d
s
d
t
+(
μ
+
)
≥
μ
,
2
α
s
2
so that, by Lemma
6.1
(ii) with
z
0
=
0,
ε
=
μ
/
2
(
μ
+
2
α
2
)
,
μ
s
(
t
)
≥
if
t
0
≤
t
<
Λ
,
(32)
2
(
μ
+
2
α
2
)
where
ln 2
μ
+
2
.
Substituting Eqs. (
28
)and(
32
) into Eq. (
17b
), we get
t
0
=
2
α
d
i
d
t
+(
γ
+
μ
)
α
μη
1
i
≥
α
1
ws
≥
α
2
)
.
2
(
μ
+
2
Applying once more Lemma
6.1
(ii) with
z
0
=
0and
α
μη
1
ε
=
α
2
)
,
4
(
γ
+
μ
)(
μ
+
2
we obtain the inequality (
30
)for
t
0
≤
t
<
Λ
with
t
0
as in Eq. (
31
).
Lemma 6.5.
Set B
=
γ
+
μ
+
ξ
2
.Then
e
−
B
(
t
−
τ
)
,
e
−
B
(
t
−
τ
)
i
(
t
)
≥
i
(
τ
)
w
(
t
)
≥
w
(
τ
)
for all
0
<
τ
<
t
<
∞
.
Indeed, this follows from the inequalities
d
i
d
t
≥−
(
γ
+
μ
)
d
w
d
t
≥−
ξ
i
,
w
.
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