Biomedical Engineering Reference
In-Depth Information
then
2
γ
μ
η
(
)
<
<
<
Λ
,
r
t
for
T
0
t
(24)
where
μ
γη
−
1
1
μ
T
0
=
T
0
(
η
)=
ln
.
(25)
Furthermore,
i
e
(
n
ω
A
−
c
η
J
)
i
if
t
(
t
)
T
0
+
τ
)
ω
(
(
≥
=
T
0
+
n
ω
+
τ
<
Λ
(26)
w
(
t
)
T
0
+
τ
)
for any positive integer n and
0
≤
τ
≤
ω
, where c is a positive constant independent
and J is the matrix
11
00
.
of
η
Proof.
From Eqs. (
17d
)and(
23
)wehave
d
r
d
t
+
μ
≤
γη
,
≤
<
Λ
.
r
0
t
−
γη
μ
Suppose
r
(
0
)
<
1. Applying Lemma
6.1
(i) with
z
0
=
1,
ε
=
1
,the
(
)=
inequality (
24
) follows with
T
0
as in Eqs. (
17a
)-(
17d
). The case
r
0
1 follows by
approximation.
Since
s
=
−
−
1
i
r
,
d
i
d
t
=
β
(
)
+
β
(
)
−
γ
−
μ
+
,
≤
<
Λ
,
t
i
t
w
i
i
F
T
0
t
1
2
where, by Eqs. (
23
)-(
24
),
|
F
|≤
const
.
η
(
i
+
w
)
≤
const
.
2
η
.
Hence
d
i
d
t
d
w
d
t
β
1
(
i
w
t
)
−
γ
−
μ
−
c
ηβ
2
(
t
)
−
c
η
≥
ξ
(
t
)
−
ξ
(
t
)
i
w
=(
A
(
t
)
−
c
η
J
)
,
(27)
where
c
is a constant independent of
η
,andEq.(
26
) follows by integration.
Lemma 6.3.
If i
(
t
)
≥
η
for
0
≤
t
<
Λ
,forsome
η
>
0
,then
)
≥
ξ
1
2
1
ξ
2
ln 2
w
(
t
ξ
2
η
for
≤
t
<
Λ
.
(28)
Proof.
Since
d
w
d
t
+
ξ
2
w
≥
ξ
1
i
≥
ξ
1
η
,
Search WWH ::
Custom Search