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Lemma B.3.18
Fo r u
0
∈
K
·
H
and f
∈
S(
0
,T)
,
and any h, k >
0,
one has
C
E(h,T )
E(k,T )
,
U
h
(t)
−
U
k
(t)
I(
0
,T )
≤
+
(B.74)
with E(h,T ) as in Lemma
B.3.14
.
In particular
,
{
U
h
(t)
}
h>
0
is Cauchy in I(
0
,T)
and there exists
=
∈
u
lim
h
→
0
U
h
(t)
I(
0
,T).
Proof
We choose in (
B.73
)
v
U
h
(t)
for some
h>
0, and then exchange in the
resulting inequality the roles of
k
and
h
. Adding the resulting two inequalities for
the difference
w(t)
=
U
h
(t)
, we ge
t a
n inequality of the type considered in
Lemma
B.3.6
, with
s(t)
replaced by
s(t)
:=
U
k
(t)
−
f(t)
: To determine
r(t)
in
(
B.40
), we estimate the last term in the bound (
B.73
)asfollows:using0
+
f
k
(t
+
k)
−
≤
k
(t)
≤
1
and
U
k
(t),
kU
k
(t)
k
(t)
−
V
∗
,
V
≤
0
,
(B.75)
we have
A
V
∗
,
V
kU
k
(t)
0
≤
r(t)
:=
u
k
(t
+
k)
−
f
k
(t
+
k),
−
≤
β
H
kU
k
(t)
u
k
(t
+
k)
V
+
f
k
(t
+
k)
V
.
Hence, in (
B.42
),
T
R(T )
=
r(t)
d
t
0
Const
S(
0
,T
+
k)
·
kU
k
(t)
≤
u
k
(t
+
k)
I(
0
,T )
+
f
k
(t)
I(
0
,T )
.
From (
B.56
), we get
R(T )
Const
S(
0
,T
+
k)
kU
k
(t)
≤
w
0
H
+
f
k
(t)
I(
0
,T )
,
and (
B.61
)gives
Const
S(
0
,T
+
k)
E(k,T ).
R(T )
≤
w
0
H
+
f
k
(t)
(B.76)
To estimate the value of
w(
0
)
H
in (
B.76
) and in (
B.43
), we use that, by
Lemma
B.3.2
,
w(
0
)
H
=
(u
k,
1
−
P
u
0
)
−
(u
h,
1
−
P
u
0
)
H
≤
E(k,T )
+
E(h,T ),
which, inserted into Lemma
B.3.6
, implies the assertion.
We can now give the proof of Theorem
B.2.2
(i). Lemma
B.3.18
established that
u
h
}
h>
0
is Cauchy in
I(
0
,T)
, hence in particular in
L
2
(J
)
and in
L
∞
(J
{
;
V
;
H
)
.
C
0
(J
Th
erefore,
u(t)
∈
;
H
)
and
u(
0
)
=
lim
k
→
0
U
k
(
0
)
=
lim
k
→
0
u
k,
1
=
P
u
0
∈
·
H
, which is the third line in (
B.6
).
To show that
u(t)
is a solution of the PVI, pick in (
B.73
)
v(t)
satisfying (
B.7b
),
and pass in (
B.73
) to the limit
k
→
K
0, implying the second line of (
B.6
); since
K
is
u
in
L
∞
(J
closed in
)
,wealsohavethefirstlineof(
B.6
).
The uniqueness and Theorem
B.2
(ii) will follow from
H
and
U
h
→
;
H
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