Digital Signal Processing Reference
In-Depth Information
If we know the transfer function HðzÞ and z-transform of the input XðzÞ , we are able to determine the
system response yðnÞ by finding the inverse z-transform of the output YðzÞ :
yðnÞ¼Z 1
fYðzÞg
(6.11)
EXAMPLE 6.7
Given a transfer function depicting a DSP system
z þ 1
z 0:5
HðzÞ¼
determine
a.
the impulse response hðnÞ,
b.
step response yðnÞ, and
n uðnÞ.
c.
system response yðnÞ if the input is given as xðnÞ¼ð0:25Þ
Solution:
a. The transfer function can be rewritten as
H ð z z ¼
z þ 1
zðz 0:5Þ ¼
A
z þ
B
z 0:5
where
z¼0 ¼2 and B ¼
z¼0:5 ¼ 3
z þ 1
ðz 0:5Þ
z þ 1
z
A ¼
Thus we have
H ð z z ¼ z þ
3
z 0:5
and
z ¼2 þ
z þ
3
z 0:5
3z
z 0:5
HðzÞ¼
By taking the inverse z-transform as shown in Equation (6.8) , we yield the impulse response
n uðnÞ
hðnÞ¼2dðnÞþ3ð0:5Þ
z
z 1 , we can determine the z-transform of the step
b. For the step input xðnÞ¼uðnÞ and its z-transform X ðzÞ¼
response as
z þ 1
z 0:5
z
z 1
Y ðzÞ¼HðzÞX ðzÞ¼
Applying the partial fraction expansion leads to
Y ð z z ¼
z þ 1
ðz 0:5Þðz 1Þ ¼
A
z 0:5 þ
B
z 1
 
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