Digital Signal Processing Reference
In-Depth Information
The transfer function HðzÞ can be factored into the pole-zero form:
b
0
ð
z
z
1
Þð
z
z
2
Þ/ð
z
z
M
Þ
ðz p
1
Þðz p
2
Þ/ðz p
N
Þ
HðzÞ¼
(6.7)
where the zeros z
i
can be found by solving roots of the numerator polynomial, while the poles p
i
can be solved for
the roots of the denominator polynomial.
EXAMPLE 6.6
Consider the following transfer functions:
1 z
2
1 þ 1:3z
1
þ 0:36z
2
HðzÞ¼
Convert it into the pole-zero form.
Solution:
We first multiply the numerator and denominator polynomials by z
2
to achieve the advanced form in which both
numerator and denominator polynomials have positive powers of z, that is,
ð1 z
2
Þz
2
ð1 þ 1:3z
1
þ 0:36z
2
Þz
2
¼
z
2
1
z
2
þ 1:3z þ 0:36
HðzÞ¼
Letting z
2
1 ¼ 0, we get z ¼ 1andz ¼1. Setting z
2
þ 1:3z þ 0:36 ¼ 0leadstoz ¼0:4andz ¼0:9.
We then can write numerator and denominator polynomials in the factored form to obtain the pole-zero form:
HðzÞ¼
ð
z
1Þð
z
þ 1Þ
ðz þ 0:4Þðz þ 0:9Þ
6.2.1
Impulse Response, Step Response, and System Response
The impulse response
hðnÞ
of the DSP system
HðzÞ
can be obtained by solving its difference equation
using a unit impulse input
dðnÞ
. With the help of the z-transform and noticing that
XðzÞ¼Zfdð
n
Þg
1,
we yield
hðnÞ¼Z
1
fHðzÞXðzÞg ¼ Z
1
fHðzÞg
(6.8)
Similarly, for a step input, we can determine step response assuming zero initial conditions. Letting
z
z
1
XðzÞ¼Z½uðnÞ ¼
the step response can be found as
yðnÞ¼Z
1
HðzÞ
z
z
1
(6.9)
Furthermore, the z-transform of the general system response is given by
YðzÞ¼HðzÞXðzÞ
(6.10)
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