Digital Signal Processing Reference
In-Depth Information
The transfer function HðzÞ can be factored into the pole-zero form:
b 0 ð z z 1 Þð z z 2 Þ/ð z z M Þ
ðz p 1 Þðz p 2 Þ/ðz p N Þ
HðzÞ¼
(6.7)
where the zeros z i can be found by solving roots of the numerator polynomial, while the poles p i can be solved for
the roots of the denominator polynomial.
EXAMPLE 6.6
Consider the following transfer functions:
1 z 2
1 þ 1:3z 1 þ 0:36z 2
HðzÞ¼
Convert it into the pole-zero form.
Solution:
We first multiply the numerator and denominator polynomials by z 2 to achieve the advanced form in which both
numerator and denominator polynomials have positive powers of z, that is,
ð1 z 2 Þz 2
ð1 þ 1:3z 1 þ 0:36z 2 Þz 2 ¼
z 2 1
z 2 þ 1:3z þ 0:36
HðzÞ¼
Letting z 2 1 ¼ 0, we get z ¼ 1andz ¼1. Setting z 2 þ 1:3z þ 0:36 ¼ 0leadstoz ¼0:4andz ¼0:9.
We then can write numerator and denominator polynomials in the factored form to obtain the pole-zero form:
HðzÞ¼ ð z 1Þð z þ 1Þ
ðz þ 0:4Þðz þ 0:9Þ
6.2.1 Impulse Response, Step Response, and System Response
The impulse response hðnÞ of the DSP system HðzÞ can be obtained by solving its difference equation
using a unit impulse input dðnÞ . With the help of the z-transform and noticing that XðzÞ¼Zfdð n Þg 1,
we yield
hðnÞ¼Z 1
fHðzÞXðzÞg ¼ Z 1
fHðzÞg
(6.8)
Similarly, for a step input, we can determine step response assuming zero initial conditions. Letting
z
z 1
XðzÞ¼Z½uðnÞ ¼
the step response can be found as
yðnÞ¼Z 1
HðzÞ z
z 1
(6.9)
Furthermore, the z-transform of the general system response is given by
YðzÞ¼HðzÞXðzÞ
(6.10)
 
Search WWH ::




Custom Search