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Q, S 0
Q, S
FIGURE 8-4.2 A schematic of a CSTR.
r S
n
r P
n
From stoichiometry,
¼
. Thus
S
P
QS
0
QS
V ¼ Dð
r P ¼r S ¼
S
0
S
Þ
(E8-4.13)
D ¼ Q=V ¼ 15=5000=min ¼ 310 3 min 1
Therefore, the mole balance Eqn (E8-4.13) is a straight line on the (S, r P ) plane with a negative
slope of
10 3 min 1 ) and intercept on the S-axis of S 0 ¼
D (
3
60 mmol/L. Plot the mole
balance line (red line) on to the Fig. 8-4.1 yields Fig. 8-4.3 .
0.20
0.18
0.16
0.14
0.12
0.10
0.08
0.06
0.04
0.02
0.00
0
10
20
30
40
50
60
S , mmol/L
FIGURE 8-4.3
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