Geography Reference
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+O 3 s ,
y 1
ρ
y 0 + s 02 y 1
y 0 2
+ s 11 x 1
ρ
ρ
y 2 = y 1 + ρ t 00 + t 10 x 1
ρ + t 01 y 1
ρ − y 0 + t 20 x 1
2
+
ρ
(15.124)
+O 3 t .
y 1
y 0 + t 02 y 1
y 0 3
+ t 11 x 1
ρ
ρ
ρ
The coecients
are collected in Box 15.12 and are computed by MATHEMATICA up to
order five as a polynomial in terms of L 01
{
s ij ,t ij }
L 02 . Figure 15.19 outlines the transformation steps
of various orders. It should be noted that the explicit formula manipulation of the coecients
{
s ij ,t ij }
in Box 15.12 was restricted by the postulate x 1 = x 2 and y 1 = y 2 if L 01
L 02 =0holds!
Box 15.12 (Conformal polynomial
{
x 2 = X ( x 1 ,y 1 ) ,y 2 = Y ( x 1 ,y 1 )
}
, coecients
{
s ij ,t ij }
).
s 00 = A 1 ( L 01 L 02 )cos B 0
(1
E 2 sin 2 B 0 ) 1 / 2
L 02 ) 3 cos B 0 (1
2sin 2 B 0 + E 2 sin 4 B 0 )
+ A 1 ( L 01
+
E 2 sin 2 B 0 ) 1 / 2
6(1
E 2 )(1
L 02 ) 5 cos B 0 [5
E 2
28 sin 2 B 0
16 E 2 sin 2 B 0 +24sin 4 B 0
+ A 1 ( L 01
+86 E 2 sin 4 B 0 +
+26 E 4 sin 4 B 0
72 E 2 sin 6 B 0
100 E 4 sin 6 B 0
12 E 6 sin 6 B 0
+77 E 4 sin 8 B 0 +39 E 6 sin 8 B 0
28 E 6 sin 10 B 0 ] 120(1
E 2 sin 2 B 0 ) 1 / 2 1 ,
E 2 ) 3 (1
L 02 ) 2 (1
2sin 2 B 0 + E 2 sin 4 B 0 )
2(1
s 10 = ( L 01
+
E 2 )
16 E 2 sin 2 B 0 +24sin 4 B 0
+86 E 2 sin 4 B 0 +
+26 E 4 sin 4 B 0 72 E 2 sin 6 B 0 100 E 4 sin 6 B 0 12 E 6 sin 6 B 0
+77 E 4 sin 8 B 0 +39 E 6 sin 8 B 0
L 02 ) 4 [5
E 2
28 sin 2 B 0
+( L 01
28 E 6 sin 10 B 0 ][24(1
E 2 ) 3 ] 1 ,
s 01 =
( L 01
L 02 )sin B 0
L 02 ) 3 sin B 0 [5
E 2
6sin 2 B 0
6 E 2 sin 2 B 0 +9 E 2 sin 4 B 0 +
( L 01
(15.125)
 
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