Geography Reference
In-Depth Information
+O
3
s
,
y
1
ρ
−
y
0
+
s
02
y
1
y
0
2
+
s
11
x
1
ρ
ρ
−
y
2
=
y
1
+
ρ
t
00
+
t
10
x
1
ρ
+
t
01
y
1
ρ
− y
0
+
t
20
x
1
2
+
ρ
(15.124)
+O
3
t
.
y
1
y
0
+
t
02
y
1
y
0
3
+
t
11
x
1
ρ
−
ρ
−
ρ
The coecients
are collected in Box
15.12
and are computed by MATHEMATICA up to
order five as a polynomial in terms of
L
01
−
{
s
ij
,t
ij
}
L
02
. Figure
15.19
outlines the transformation steps
of various orders. It should be noted that the explicit formula manipulation of the coecients
{
s
ij
,t
ij
}
in Box
15.12
was restricted by the postulate
x
1
=
x
2
and
y
1
=
y
2
if
L
01
−
L
02
=0holds!
Box 15.12 (Conformal polynomial
{
x
2
=
X
(
x
1
,y
1
)
,y
2
=
Y
(
x
1
,y
1
)
}
, coecients
{
s
ij
,t
ij
}
).
s
00
=
A
1
(
L
01
−
L
02
)cos
B
0
(1
E
2
sin
2
B
0
)
1
/
2
−
L
02
)
3
cos
B
0
(1
2sin
2
B
0
+
E
2
sin
4
B
0
)
+
A
1
(
L
01
−
−
+
E
2
sin
2
B
0
)
1
/
2
6(1
−
E
2
)(1
−
L
02
)
5
cos
B
0
[5
E
2
28 sin
2
B
0
16
E
2
sin
2
B
0
+24sin
4
B
0
+
A
1
(
L
01
−
−
−
−
+86
E
2
sin
4
B
0
+
+26
E
4
sin
4
B
0
−
72
E
2
sin
6
B
0
−
100
E
4
sin
6
B
0
−
12
E
6
sin
6
B
0
+77
E
4
sin
8
B
0
+39
E
6
sin
8
B
0
−
28
E
6
sin
10
B
0
]
120(1
E
2
sin
2
B
0
)
1
/
2
−
1
,
E
2
)
3
(1
−
−
−
L
02
)
2
(1
2sin
2
B
0
+
E
2
sin
4
B
0
)
2(1
s
10
=
(
L
01
−
−
+
−
E
2
)
16
E
2
sin
2
B
0
+24sin
4
B
0
+86
E
2
sin
4
B
0
+
+26
E
4
sin
4
B
0
−
72
E
2
sin
6
B
0
−
100
E
4
sin
6
B
0
−
12
E
6
sin
6
B
0
+77
E
4
sin
8
B
0
+39
E
6
sin
8
B
0
L
02
)
4
[5
E
2
28 sin
2
B
0
−
+(
L
01
−
−
−
−
28
E
6
sin
10
B
0
][24(1
E
2
)
3
]
−
1
,
−
−
s
01
=
−
(
L
01
−
L
02
)sin
B
0
−
L
02
)
3
sin
B
0
[5
E
2
6sin
2
B
0
−
6
E
2
sin
2
B
0
+9
E
2
sin
4
B
0
+
−
(
L
01
−
−
−
(15.125)
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