Civil Engineering Reference
In-Depth Information
VRwx
2
=- =
15 000
,
-
200 15
(
)
=
12 000
,
lb shearatgrid line2
1
V
D
12 000
50
,
2
v
=
=
=
240
plfunitshear on
left side of grid line2
2
L
left
V
D
12 000
40
,
v
=
2
=
=
300
plfunitshear on
rightsideofgrid line2
2
R
right
VRwx
3
=- =
15 000
,
-
200 35
(
)
=
8000
lbshear at grid line3
1
V
D
8000
40
v
=
3
=
=
200
plfunitshear on le
ft side of grid line3
3
L
left
V
D
8000
50
3
v
=
=
=
160
plfunitshear on r
ight side of grid line3
3
R
right
VRwx
4
=-=
8000
-
200 15
()
=
5000
lb shearatgrid linee4
5
R
D
5000
50
v
== =
5
100
plfunitshear at grid line
4
4
Determination of the chord force at grid line 2B:
MR
wx
2
2
200 15
2
()
2
=- =
15 000 15
,
(
)
-
=
202 500
,
ft
-lb
B
1
2
M
D
202 500
40
,
F
=
2
B
=
=
5062 5
.
lb tension
2
B
Determination of the chord force at grid line 3B:
2
2
MR
wx
3
200 35
2
()
=- =
15 000 35
,
(
)
-
=
402 500
,
ft-lb
B
1
2
M
D
402 500
40
,
F
=
3
B
=
=
10 062 5
,
.
lb tension
3
B
Determination of left transfer diaphragm shears (see Fig. 4.2):
Disrupted chord force = 5062.5 lb at grid line 2B
V
D
5062 510
50
.( )
1012 5
15
.
V
=
=
1012 5
.
lb
v
=
A
TD
=
=
67 5
.plf
A
A
The reaction of the transfer diaphragm at A is acting to the left. Applying the
remaining shears on the sheathing element shows that the transfer diaphragm shear
is positive.
V
D
5062 540
50
.( )
== =
-
4050
15
C
V
=
=
4050
lb
v
v
=-270 plf
C
C
A
TD
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