Civil Engineering Reference
In-Depth Information
The maximum bending force per unit weld length can be determined from
equation 9.50b as
F
Ty
,
Ed
=
(
−
0.05
Q
×
10
6
)
×
(
268.7
/
2
)
2
×
268.7
3
/
12
=
2.078
Q
N
/
mm.
Using equation 9.30, the resultant of these is
F
w
,
Ed
=
√
[
(
1.861
Q
)
2
+
(
2.078
Q
)
2
]=
2.789
Q
N
/
mm.
For S355 Grade steel,
β
w
=
0.9
EC3-1-8T4.1
f
vw
,
d
=
510
/
√
3
0.9
×
1.25
=
261.7N
/
mm
2
EC3-1-8 4.5.3.3
F
w
,
Rd
=
261.7
×
6
/
√
2
=
1110N
/
mm.
EC3-1-8 4.5.3.3
Hence 2.789
Q
≤
1110,
so that
Q
w
≤
398.1
<
443.0
(
≥
Q
p
)
Using the directional method of EC3-1-8 with equations 9.32-9.34,
σ
⊥
=
(
−
0.05
Q
×
10
6
)
×
(
268.7
/
2
)
sin45
o
=−
0.346
Q
N
/
mm
2
2
×
(268.7
3
/
12
)
×
(
6
/
√
2
)
τ
⊥
=
(
−
0.05
Q
×
10
6
)
×
(
268.7
/
2
)
cos45
o
2
×
(268.7
3
/
12
)
×
(
6
/
=−
0.346
Q
N
/
mm
2
√
2
)
Q
×
10
3
2
×
268.7
×
(
6
/
=
0.439N
/
mm
2
τ
||
=
√
2
)
The strength condition is
510
0.9
×
1.25
EC3-1-8 4.5.3.2(6)
{
(
−
0.346
Q
)
2
+
3
×[
(
−
0.346
Q
)
2
+
(
0.439
Q
)
2
]}
0.5
≤
so that
Q
w
≤
441.0
<
443.0
(
≥
Q
p
)
and
0.346
Q
≤
0.9
×
510
/
1.25
so that
Q
w
≤
1060
>
441.0.
Thus the connection capacity is governed by the shear and bending resistance
of the welds.
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