Civil Engineering Reference
In-Depth Information
The maximum bending force per unit weld length can be determined from
equation 9.50b as
F Ty , Ed = ( 0.05 Q × 10 6 ) × ( 268.7 / 2 )
2 × 268.7 3 / 12
= 2.078 Q N / mm.
Using equation 9.30, the resultant of these is
F w , Ed = [ ( 1.861 Q ) 2 + ( 2.078 Q ) 2 ]= 2.789 Q N / mm.
For S355 Grade steel, β w = 0.9
EC3-1-8T4.1
f vw , d = 510 / 3
0.9 × 1.25 = 261.7N / mm 2
EC3-1-8 4.5.3.3
F w , Rd = 261.7 × 6 / 2 = 1110N / mm.
EC3-1-8 4.5.3.3
Hence 2.789 Q 1110,
so that Q w 398.1 < 443.0 ( Q p )
Using the directional method of EC3-1-8 with equations 9.32-9.34,
σ = ( 0.05 Q × 10 6 ) × ( 268.7 / 2 ) sin45 o
=− 0.346 Q N / mm 2
2 × (268.7 3 / 12 ) × ( 6 / 2 )
τ = ( 0.05 Q × 10 6 ) × ( 268.7 / 2 ) cos45 o
2 × (268.7 3 / 12 ) × ( 6 /
=− 0.346 Q N / mm 2
2 )
Q × 10 3
2 × 268.7 × ( 6 /
= 0.439N / mm 2
τ || =
2 )
The strength condition is
510
0.9 × 1.25
EC3-1-8 4.5.3.2(6)
{ ( 0.346 Q ) 2 + 3 ×[ ( 0.346 Q ) 2 + ( 0.439 Q ) 2 ]} 0.5
so that
Q w 441.0 < 443.0 ( Q p )
and
0.346 Q 0.9 × 510 / 1.25
so that
Q w 1060 > 441.0.
Thus the connection capacity is governed by the shear and bending resistance
of the welds.
 
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