Geology Reference
In-Depth Information
Fig. 2.2 Cartesian ( x , y , z )
and spherical ( r ,™,¥)
coordinates of a point P in
the geographic reference
frame
meridian and 90 ı E. Clearly, a point in the city
of London, on the Eurasian plate, has constant
longitude ¥ D 0 in this reference frame (Fig. 2.2 ).
In plate kinematics, the Earth is assumed to
have a spherical shape, so that the Cartesian
coordinates ( x , y , z ) of a point at distance r from
the Earth's centre are related to the geographic
coordinates (™,¥), colatitude and longitude, by
the following equations:
8
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Another useful geocentric reference frame is
the geomagnetic coordinate system (e.g., Camp-
bell 2003 ). This frame is built on the basis of the
observation that the present day Earth's magnetic
field can be approximated as the field generated
by a magnetic dipole placed at the Earth's centre,
as we shall see in Chap. 4 . Such a dipole has
not fixed direction, but precedes irregularly about
the North Pole according to the so-called secular
variation of the core field. It is mathematically
represented by a magnetic moment vector, m ,
which currently (December 31st 2013) points to
a location placed in the southern hemisphere, at
about (80.24 ı S, 107.46 ı E). This location is called
the geomagnetic South Pole , and its antipodal
point at (80.24 ı N, 72.54 W) is known as the ge-
omagnetic North Pole . The axis passing through
these two points defines the z -axis of the geomag-
netic reference frame. The x -axis of this coordi-
nate system is chosen in such a way that the prime
meridian passes through the geographic South
Pole. Finally, the y -axis will be also placed in the
geomagnetic dipole equator, 90 ı from the x -axis.
x D r sin ™ cos ¥
y D r sin ™ sin ¥
z D r cos ™
(2.27)
:
Figure 2.2 illustrates the relation between
Cartesian and geographic (spherical) coordinates
of a point. Equations 2.27 can be easily inverted
to get an expression of the spherical coordinates
as a function of the Cartesian components:
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¥ D arctan .y=x/
D ar ccos. z =r/
(2.28)
r D p x 2
:
C y 2
C z 2
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