Environmental Engineering Reference
In-Depth Information
2.6.2 Spherical Domain
For a spherical domain, the boundary conditions are not separable for
x
,
y
and
z
in
a Cartesian coordinate system, like in the case of a circular domain in Section 2.5.2.
A spherical coordinate transformation of
⎧
⎨
x
=
r
sin
θ
cos
ϕ
,
0
≤
ϕ
≤
2
π
,
y
=
r
sin
θ
sin
ϕ
,
0
≤
θ
≤
π
,
⎩
z
=
r
cos
θ
,
0
<
r
≤
a
0
is required before applying the method of separation of variables. In the spherical
coordinate system, PDS (2.52) reads
⎧
⎨
a
2
u
tt
=
Δ
u
(
r
,
θ
,
ϕ
,
t
)+
F
(
r
,
θ
,
ϕ
,
t
)
0
<
θ
<
π
,
0
<
r
<
a
0
,
0
<
t
,
|
u
(
0
,
θ
,
ϕ
,
t
)
| <
∞
,
(2.54)
⎩
L
(
u
,
u
r
)
|
r
=
a
0
=
0
,
u
(
r
,
θ
,
ϕ
+
2
π
,
t
)=
u
(
r
,
θ
,
ϕ
,
t
)
,
u
(
r
,
θ
,
ϕ
,
0
)=
Φ
(
r
,
θ
,
ϕ
)
,
u
t
(
r
,
θ
,
ϕ
,
0
)=
Ψ
(
r
,
θ
,
ϕ
)
,
where the Laplacian is
r
2
sin
2
∂ϕ
r
2
∂
1
∂
∂
1
r
2
sin
∂
∂θ
∂
∂θ
1
r
2
sin
2
∂
Δ
=
+
+
2
.
θ
∂
r
r
θ
θ
It can be shown by following a similar approach to that in Section 2.5.2 that the
solution structure theorem is also valid in a spherical coordinate system. We thus
focus on seeking
u
=
W
Ψ
(
r
,
θ
,
ϕ
,
t
)
, the solution for the case
Φ
=
F
=
0.
Separation of Variables
Assume a solution of type
u
. Substituting it into the wave equation
in PDS (2.54) and denoting the separation constant
=
v
(
r
,
θ
,
ϕ
)
T
(
t
)
k
2
, we obtain
−
k
2
v
Δ
v
+
=
0
,
v
(
r
,
θ
,
ϕ
+
2
π
)=
v
(
r
,
θ
,
ϕ
)
,
(2.55)
|
v
(
0
,
θ
,
ϕ
)
| <
∞
,
0
<
r
<
a
0
,
0
<
θ
<
π
,
T
(
2
T
t
)+(
ka
)
(
t
)=
0
.
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