Civil Engineering Reference
In-Depth Information
s
a
Fsin
a
4 m
D
3
B
A
b
s
10 m
5 m
25 m
g
vk
= 77.1 kN/m
450 kN
450 kN
q
vk
= 45.65 kN/m
1.2 m
450 kN
450 kN
q
vk
= 45.65 kN/m
1.2 m
1.6
0. 4
0.352
-
+
0.952
1
1.6
3.57 m
1.43
Figure 4.186 Determination of the force in diagonal member D
3
using the influence
line method.
F
Ed
D
ð
maximum
¼
925
:
1
1
:
3 + 1542
1
:
35
¼
3284
:
3 kN Tension force
ð
Þ
F
Ed
D
ð
minimum
¼F
D
:
L
:
g
g
+
F
L
:
L
:
g
q
F
Ed
D
ð
minimum
¼
925
:
1
1
:
3
492
:
6
1
:
35
¼
537
:
6 kN Tension force
ð
Þ
4.6.3.8 Calculation of Force in the Diagonal Chord Member D
2
The force in the diagonal truss member D
2
can be calculated, as shown in
Figure 4.187
, as follows:
A
ve
D
ðÞ¼
0
:
5
34
:
29
1
:
2
¼
20
:
57
A
+ve
D
ðÞ¼
0
:
5
5
:
71
0
:
2
¼
0
:
57
A
net
D
ðÞ¼
20
:
57 + 0
:
57
¼
20
:
0
F
D
:
L
:
D
ðÞ¼
20
77
:
1
¼
1542 kN
F
L
:
L
:
D
ðÞ
negative
ð
Þ ¼
450
1
ð
:
2+1
:
152
Þ
20
:
57
45
:
65
7
:
5
0
ð
:
2+0
:
152
Þ
0
:
57
2
:
45
¼
2001
:
5kN
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