Civil Engineering Reference
In-Depth Information
s
a
Fsin a
4 m
D 3
B
A
b
s
10 m
5 m
25 m
g vk = 77.1 kN/m
450 kN
450 kN
q vk = 45.65 kN/m
1.2 m
450 kN
450 kN
q vk = 45.65 kN/m
1.2 m
1.6
0. 4
0.352
-
+
0.952
1
1.6
3.57 m
1.43
Figure 4.186 Determination of the force in diagonal member D 3 using the influence
line method.
F Ed D ð maximum ¼ 925
:
1 1
:
3 + 1542 1
:
35
¼ 3284
:
3 kN Tension force
ð
Þ
F Ed D ð minimum ¼F D : L : g g + F L : L : g q
F Ed D ð minimum ¼ 925
:
1 1
:
3 492
:
6 1
:
35
¼ 537
:
6 kN Tension force
ð
Þ
4.6.3.8 Calculation of Force in the Diagonal Chord Member D 2
The force in the diagonal truss member D 2 can be calculated, as shown in
Figure 4.187 , as follows:
A ve D ðÞ¼ 0
:
5 34
:
29 1
:
2 ¼ 20
:
57
A +ve D ðÞ¼ 0
:
5 5
:
71 0
:
2 ¼ 0
:
57
A net D ðÞ¼ 20
:
57 + 0
:
57 ¼ 20
:
0
F D : L : D ðÞ¼ 20 77
:
1 ¼ 1542 kN
F L : L : D ðÞ negative
ð
Þ ¼ 450 1
ð
:
2+1
:
152
Þ 20
:
57 45
:
65 7
:
5
0
ð
:
2+0
:
152
Þ 0
:
57 2
:
45 ¼ 2001
:
5kN
 
 
 
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