Biomedical Engineering Reference
In-Depth Information
5.7.3 Proof of Eq.
(
5.103
)
Next, the proof of Eq. (
5.103
) is presented, which is
E
A
AR
uu
A
T
=
¯
AR
uu
¯
A
T
+
ʛ
−
1
tr
(
R
uu
ʨ
) .
The proof is quite similar to the one provided in Sect.
5.7.1
.First,wehave
AR
uu
A
T
[
]
i
,
j
=
A
i
,
k
[
R
uu
]
k
,
A
j
,
=
[
R
uu
]
k
,
A
i
,
k
A
j
,
.
k
,
k
,
Using Eq. (
5.168
),we get
E
A
]
i
,
j
1
ʻ
j
[
ʨ
−
1
AR
uu
A
T
R
uu
]
k
,
A
i
,
k
A
j
,
+
[
=
[
[
R
uu
]
k
,
ʴ
i
,
j
]
k
,
.
k
,
k
,
(5.177)
The first term on the right-hand side of the equation above is rewritten as
A
j
,
=[
¯
AR
uu
¯
A
T
R
uu
]
k
,
A
i
,
k
[
]
i
,
j
.
k
,
Considering
R
uu
]
k
,
[
ʨ
−
1
R
uu
ʨ
−
1
[
]
k
,
=
tr
(
),
(5.178)
k
,
the second term in Eq. (
5.177
) is rewritten as
1
ʻ
j
[
ʨ
−
1
]
k
,
=[
ʛ
−
1
R
uu
ʨ
−
1
[
R
uu
]
k
,
ʴ
i
,
j
]
i
,
j
tr
(
).
(5.179)
k
,
Consequently, we get the following relationship:
]=
¯
AR
uu
¯
A
T
AR
uu
A
T
+
ʛ
−
1
tr
R
uu
ʨ
−
1
E
A
[
(
).
(5.180)
5.7.4 Proof of Eq.
(
5.166
)
Next, the proof of Eq. (
5.166
) is presented. To derive this equation, we should consider
log
p
(
y
|
z
,
A
)
and log
p
(
A
)
, because
ʛ
is contained in these two terms. We have