Biomedical Engineering Reference
In-Depth Information
5.7.2 Proof of Eq.
(
5.94
)
We provide a proof of Eq. (
5.94
), which is repeated here for convenience.
K
K
1
2
1
2
T
u
k
u
k
E
−
1
(
y
k
−
Au
k
)
ʛ
(
y
k
−
Au
k
)
−
(
A
,
u
)
k
=
k
=
1
K
K
1
2
1
2
y
k
ʛ
u
k
ʓ
¯
=−
y
k
+
1
¯
u
k
.
j
=
1
j
=
The left-hand side of the equation above is changed to:
K
K
1
2
1
2
T
u
k
u
k
E
−
1
(
y
k
−
Au
k
)
ʛ
(
y
k
−
Au
k
)
−
(
A
,
u
)
k
=
k
=
1
K
1
2
y
k
ʛ
=−
y
k
k
=
1
−
u
k
u
k
K
1
2
u
k
A
T
y
k
ʛ
u
k
A
T
−
E
(
A
,
u
)
ʛ
y
k
−
Au
k
+
ʛ
Au
k
+
.
k
=
1
(5.174)
On the right-hand side of Eq. (
5.174
), the following relationship:
u
k
u
k
u
k
E
u
u
k
E
A
A
T
A
I
u
k
A
T
E
ʛ
Au
k
+
=
ʛ
+
(
A
,
u
)
E
u
u
k
I
u
k
¯
A
T
ʛ
¯
A
ʨ
−
1
=
+
M
+
E
u
u
k
ʓ
u
k
E
u
tr
u
k
u
k
ʓ
=
=
tr
E
u
u
k
u
k
tr
u
k
+
ʓ
−
1
=
ʓ
=
(
¯
u
k
¯
)
ʓ
u
k
ʓ
¯
= ¯
u
k
(5.175)
holds, where constant terms are omitted. In the equation above, we use Eq. (
5.56
).
Also, the relationship,
y
k
ʛ
y
k
¯
A
T
u
k
A
T
y
k
ʛ
¯
A
u
k
E
Au
k
+
ʛ
=
u
k
+ ¯
¯
ʛ
y
k
(
A
,
u
)
¯
A
T
y
k
ʛ
¯
A
ʓ
−
1
u
k
ʓʓ
−
1
=
ʓ
¯
u
k
+ ¯
ʛ
y
k
u
k
ʓ
¯
=
2
¯
u
k
(5.176)
holds. Substituting Eqs. (
5.175
) and (
5.176
)into(
5.174
), we get Eq. (
5.94
).