Design of a column - Reinforced Concrete with FRP Bars: Mechanics and Design - page 348

Axial strength is

N1
f
∑ (

−

)

() ()

P: AiE ⋅ ⋅ ε i = −⋅ 211 kip

=

n5 f f f5

i0 =

Flexural strength is

N1
f
∑

−

=

h
2

() () ()

M: AiE ⋅ ⋅ ε i ⋅ − di 64.518 kipft ⋅ ⋅

=

n5 f f f5 f

i0 =

The strength reduction factor is

( )

ε N1

2

−

f5 f

0.65 if 1.15 − ≤ 0.65

ε

fu

( )

ε N1

2

−

φ :

=

f5 f

5

1.15 −

ε

fu

( )

ε N1

2

−

f5 f

0.75 if 1.15 − ≥ 0.75

ε

fu

φ= 0.65

5

9.5.6 Point 6—Pure tension

ε fu = 0.01

h = 20 in

The strain in FRP reinforcement is

ε f6 εf6(i) := -ε fu
Axial strength is

N1
f
∑ (

−

) () ()

⋅ ⋅ ε =− ⋅

P: = AiE i 358 kip

n6

f f f6

i0 =