Civil Engineering Reference
In-Depth Information
Axial strength is
N1
f
−
∑
(
)
(
)
()
()
P:0.85 fb0.8c
=
⋅ ′ ⋅⋅
⋅
+
AiE
⋅
⋅ ε
if5
n4
c
4
f
f
f4
i0
=
P
n4
= 91·kip
Flexural strength
N1
−
f
∑
h
2
+
h
2
(
)
(
)
()
()
M:0.85 fb0.8c
=
⋅ ′ ⋅⋅
⋅
⋅
−⋅
0.4c
AiE
⋅
⋅ε
if5
⋅
−
d(i)
n4
c
4
4
f
f
f4
f
i0
=
M
=⋅
266 kipft
⋅
n4
Strength reduction factor
(
)
ε
N1
2
−
f4
f
0.65
if 1.15
−
≤
0.65
φ
=
0.65
4
ε
fu
(
)
ε
N1
2
−
f4
f
φ=
:
1.15
−
4
ε
fu
(
)
ε
N1
2
−
f4
f
0.75
if 1.15
−
≥
0.75
ε
fu
9.5.5 Point 5—Neutral axis at the level
of the highest section fibers
ε
fu
= 0.01
The strain in FRP reinforcement is
−ε
()
fu
ε
(i):
⋅
di
=
if5
(
)
f
dN 1
−
f
f
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